Answer:
What if you have to push a heavy object up a ramp? Say, for example, you have to move a refrigerator. You want to go camping, and because you expect to catch plenty of fish, you decide to take your 100-kilogram refrigerator with you. The only catch is getting the refrigerator into your vehicle (see the figure). The refrigerator has to go up a 30-degree ramp that happens to have a static coefficient of friction with the refrigerator of 0.20 and a kinetic coefficient of friction of 0.15. The good news is that you have two friends to help you move the fridge. The bad news is that you can supply only 350 newtons of force each, so your friends panic.
The minimum force needed to push that refrigerator up the ramp has a magnitude Fpush, and it has to counter the component of the weight of the refrigerator acting along the ramp and the force due to friction.
The first step in this problem is to resolve the weight of the refrigerator into components parallel and perpendicular to the ramp. Take a look at the figure, which shows the refrigerator and the forces acting on it. The component of the weight of the refrigerator along the ramp is
Step-by-step explanation:
please rate thank and follow
1. F(3)= -2(3)-5
-6-5
F(3)=-11
2. F(3)= -2(3)^2-4
-6^2-4
36-4
F(3)=32
3. F(x)=−2x−5
For: x=−2, f(x) is:f(−2)=(−2×−2)−5=4−5=−1
For: x=−1, f(x) is:f(−1)=(−2×−1)−5=2−5=−3
For: x=1, f(x) is:f(1)=(−2×1)−5=−2−5=−7
For: x=2, f(x) is:f(2)=(−2×2)−5=−4−5=−9
The Range is:
{−1,−3,−7,−9}
4. -80, -110
3 miles each day for x days is 3x
5 miles each day for y days is 5y
Frank ran at least as many miles as Latoya is 3x >/= 5y
It is 62 inch squared.
All you have to do is plug the numbers into the SA formula (SA= lw + hw + hl)
D. there is a perfect association between the variables
