Ask question

Ask question

All categories

3 years ago

15

Graph the parabola 3x^2+6x-24

1 answer:

brilliants [131]3 years ago

7 0

We have the following function:
F (x) = 3x ^ 2 + 6x-24
We observe that it is a quadratic equation.
The graph is therefore a parabola.
Its cut points are:
(-4, 0)
(2, 0)
Answer:
See attached image to see graph of the function

You might be interested in

What are the domain and range of the function mc013-1

lozanna [386]

The domain and range of the function are:

<h3>How to determine the domain of the function?</h3>

In this exercise, you're given the following function f(x) = 5ˣ ⁻ ³ + 1. Next, we would equate the function to zero (0) to determine its domain as follows:

0 = 5ˣ ⁻ ³ + 1.

-1 = 5ˣ ⁻ ³

-(5⁰) = 5ˣ ⁻ ³

-0 = x - 3

x = 3.

Therefore, the domain are all real numbers and they can be substituted for x to return a valid f(x) value.

From the graph of the given function (5ˣ ⁻ ³ + 1), we can logically deduce that the range comprises all real numbers that are greater than 1.

Read more on domain here: brainly.com/question/17003159

#SPJ1

6 0

2 years ago

dem82 [27]

Answer:

it is 1.31148125 m2

Step-by-step explanation:

6 0

3 years ago

Equations in Iwo V Solve the system by the addition method. 3x+8y=6 3x-8y=6 Select the correct choice below and, if necessary, f

sweet [91]

Answer:

A. there is exactly one solution. the solution set is {(2, 0)}.

Step-by-step explanation:

3x + 8y = 6

3x - 8y = 6

when we add these 2 equations, we get

6x + 0 = 12

6x = 12

x = 2

now we use one of the original equations to get y :

3×2 + 8y = 6

6 + 8y = 6

8y = 0

y = 0

4 0

2 years ago

Read 2 more answers

Use logarithmic differentiation to find the derivative of the function. y = x2cos x Part 1 of 4 Using properties of logarithms,

Arisa [49]

ANSWER

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

EXPLANATION

The given function is

$y = {x}^{2} \cos(x)$

We take natural log of both sides;

$ln(y) = ln({x}^{2} \cos(x) )$

Recall and use the product rule of logarithms.

$ln(AB) = ln(A ) + ln(B)$

This implies that:

$ln(y) = ln({x}^{2} ) + ln( \cos(x) )$

$ln(y) = 2 ln({x} ) + ln( \cos(x) )$

We now differentiate implicitly to obtain;

$\frac{ {y}^{'} }{y} = \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) }$

Multiply through by y,

${y}^{'} = y( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) })$

Substitute y=x²cosx to obtain;

${y}^{'} = {x}^{2} \cos(x) ( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) } )$

Expand:

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

7 0

3 years ago

Write an equation o the line that passes through the given points (-1,7) and (2,-2)

RoseWind [281]

you have to. plot them on a lumber line

7 0

2 years ago