4 years ago

Find the area of EFG

Mathematics

1 answer:

Arturiano [62]4 years ago

6 0

Sin^-1(5/13) to find the angle of hfg then multiply by 2 to find the angle of efg.

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Tom invested £2500 for 3 years into his savings account.

Hitman42 [59]

The frist years interest would be £75 , so after 1 year it'd be £2,575 , after 2 years the interest would be £77.25 giving a total of £2,652.25 and after the third final ear , the interest would be £79.57 , resulting in Tom having <span>£2,731.82 at the end of the 3 years</span>

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3 years ago

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Suppose a population grows according to a logistic model with initial population 1000 and carrying capacity 10,000. If the popul

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Answer:

7500

Step-by-step explanation:

1 year= 2500

3 years= x

So we got

2500 × 3 = 7500

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3 years ago

How do u write 2.45 in words

Genrish500 [490]

It would likely just be written as "two point four five", or "two and forty-five hundredths".

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The numerical course grades in a statistics course can be approximated by a normal model with a mean of 70 and a standard deviat

Naily [24]

Answer:

A = 82.82

B = 72.53

C = 61.58

D = 53.55

Step-by-step explanation:

First, determine the percentile at which the cutoff grade in each letter grade interval falls on and find the equivalent z-score:

A: (100-10) = 90-th percentile

z-score = 1.282

B: (100-10-30) = 60-th percentile

z-score = 0.253

C : (100-10-30-40) = 20-th percentile

z-score = -0.842

D: (100-10-30-40-15) = 5-th percentile

z-score = −1.645

The value 'X' for each cutoff can be found by applying the z-score equation:

$z= \frac{X- \mu }{SD}$

Where μ is the mean and SD is the standard deviation

Therefore, the cutoffs are:

$1.282= \frac{X(A)- 70}{10}\\X(A) = 10*1.282 +70\\X(A) = 82.82\\\\0.253 = \frac{X(B)- 70}{10}\\X(B) = 10*0.253 +70\\X(B) = 72.53\\\\0.253 = \frac{X(C)- 70}{10}\\X(C) = 10*-0.842 +70\\X(C) = 61.58\\\\0.253 = \frac{X(D)- 70}{10}\\X(D) = 10*-1.645 +70\\X(D) = 53.55\\$

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3 years ago

A plant is already 13.25 meters tall, and it will grow 9 centimeters every month. The plant's height, H (in meters), after x mon

7nadin3 [17]

H = 0.09 (20) + 13.25

H = 1.80 + 13.25

H = 15.05 m

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2 years ago

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