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Whitepunk [10]
3 years ago
10

The numerical course grades in a statistics course can be approximated by a normal model with a mean of 70 and a standard deviat

ion of 10. The professor must convert the numerical grades to letter grades. She decides that she wants 10% A's, 30% B's, 40% C's, 15% D's, and 5% F's.
What is the cutoff for an A grade?
What is the cutoff for an B grade?
What is the cutoff for an C grade?
What is the cutoff for an D grade?
Mathematics
1 answer:
Naily [24]3 years ago
6 0

Answer:

A = 82.82

B = 72.53

C = 61.58

D = 53.55

Step-by-step explanation:

First, determine the percentile at which the cutoff grade in each letter grade interval falls on and find the equivalent z-score:

A: (100-10) = 90-th percentile

z-score = 1.282

B: (100-10-30) = 60-th percentile

z-score = 0.253

C : (100-10-30-40) = 20-th percentile

z-score = -0.842

D: (100-10-30-40-15) = 5-th percentile

z-score =  −1.645

The value 'X' for each cutoff can be found by applying the z-score equation:

z= \frac{X- \mu }{SD}

Where μ is the mean and SD is the standard deviation

Therefore, the cutoffs are:

1.282= \frac{X(A)- 70}{10}\\X(A) = 10*1.282 +70\\X(A) = 82.82\\\\0.253 = \frac{X(B)- 70}{10}\\X(B) = 10*0.253 +70\\X(B) = 72.53\\\\0.253 = \frac{X(C)- 70}{10}\\X(C) = 10*-0.842 +70\\X(C) = 61.58\\\\0.253 = \frac{X(D)- 70}{10}\\X(D) = 10*-1.645 +70\\X(D) = 53.55\\

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Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5
zaharov [31]

Answer:

31

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}} or \displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}

Therefore, the solution is 31.

__________________________________________________________

Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as \displaystyle \large{a_{n-1} \cdot r = a_n} meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as:

\displaystyle \large{r=\frac{a_{n+1}}{a_n}}

Once knowing which sequence or series is it, apply an appropriate formula for the series. For geometric series, apply the following three formulas:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}\\\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

Above should be applied for series that have common ratio not equal to 1.

\displaystyle \large{S_n=a_1 \cdot n}

Above should be applied for series that have common ratio exactly equal to 1.

__________________________________________________________

Topics

Sequence & Series — Geometric Series

__________________________________________________________

Others

Let me know if you have any doubts about my answer, explanation or this question through comment!

__________________________________________________________

7 0
3 years ago
What is the side length of a cube with volume 343 in squared?
Thepotemich [5.8K]
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The formula for a square is V = s^3. Using this formula, we can plug in the volume and solve for s.

WORK:
343 = s^3
s = 7

ANSWER:
The side length of a cube with volume 343 is 7 inches.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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