Motocross The path that a motocross dirt bike rider follows during a jump is given

(HELP ASAP)

wariber [46]

Answer:

45 km^2 (C)

Step-by-step explanation:

Isolate the smaller square -

We only need two side lengths, take 3km and 3km.

3×3 = 9km^2, that's the area of the smaller square.

Isolate the larger square -

Take 6km and the other 6km

6×6 = 36km^2

Add the square's areas together to get the whole area -

36 + 9 = 45km^2

All you need to do to solve these problems is to isolate the shapes and find their area's, and finally add them together.

8 0

3 years ago

Can someone please help

Harrizon [31]

Answer:

31,41,51,71

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find the value of x. Round to the nearest tenth.

nordsb [41]

Step-by-step explanation:

here,,

a=3,b=10,C=120°

c^2=a^2+b^2-2ab cos120°

=(3)^2 +(10)^2 _2 (3)(10)(-1/2) [cos120°=-1/2]

=9+100-(-30)

=109+30

=139

c=(139 )1/2=11.79

c=12

3 0

3 years ago

Which of the following equations is equivalent to S=pi r^2 h

lara31 [8.8K]

The equation that is equivalent to S=pi r^2 h is h = S/pir^2

<h3>Subject of formula</h3>

This is a way of representing a variable with another. Given the equation

S=pi r^2 h

We are to make 'h" the subject of the formula.

Divide both sides by pir^2

S/pir^2 =pi r^2 h/pir^2

h = S/pir^2

Hence the equation that is equivalent to S=pi r^2 h is h = S/pir^2

Learn more on subject of formula here: brainly.com/question/657646

#SPJ1

4 0

2 years ago

A survey of 700 adults from a certain region asked, "What do you buy from your mobile device?" The results indicated that 59%

Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes $n_{1} = 400 and n_{2} = 300$

Proportion of mean $p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52$

Null hypothesis H0 : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

Alternative hypothesis H1:- p1 ≠ p2

a) The test statistic is

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }$

where $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

on calculation we get p = 0.56

now q =1-p = 1-0.56=0.44

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }\\ =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300} }$

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

conclusion:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) 95% confidence intervals

The confidence intervals are P± 1.96(√PQ/n)

we know that = $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of confidence intervals (0.523 ,0.596)

3 0

3 years ago