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3 years ago

Please hurry!!add the polynomials: (9x^2 - 4x + 11) (3x^2 - 2x + 2)

Mathematics

1 answer:

tangare [24]3 years ago

4 0

Answer:

12x² - 6x + 13

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients/Degrees

Step-by-step explanation:

Step 1: Set up

(9x² - 4x + 11) + (3x² - 2x + 2)

Step 2: Simplify

Combine like terms (x²): 12x² - 4x + 11 - 2x + 2
Combine like terms (x): 12x² - 6x + 11 + 2
Combine like terms (Z): 12x² - 6x + 13

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Brian irons 2/9 of his shirt in 3 3/5 minutes. At this rate, how much of his shirt does he iron each minute?

vodka [1.7K]

The speed for which Brian iron the shirts is given by:

$R = \frac{\frac{2}{9}}{3\frac{3}{5}}$

Rewriting we have:

$R = \frac{\frac{2}{9}}{\frac{18}{5}}$

$R = \frac{10}{162}$

Then, for each minute, we have the amount of ironed shirt is:

$(\frac{10}{162})(1) = \frac{10}{162}$

Answer:

At this rate, Brian plans 10/162 of his shirt.

8 0

3 years ago

Read 2 more answers

A van and a bicycle move towards each other. The speed of the van is 80 km per hour, and the speed of the bike is 20 km per hour

otez555 [7]

-- :

Bike > ________300km_________< Van

20km/h 80km/h

In one hour, the bike will have moved 20km and the van would have moved 80km.

The distance between them was 300km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

300km-(20km+80km) = 200km

So now the distance between them is 200km.

Now another hour passes. The distance between them was 200km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

200km-(20km+80km) = 100km

So now the distance between them is 100km

Now another hour passes. The distance between them was 100km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

100km-(20km+80km) = 0km

So now the distance between them is 0km, which means they have met. If we count, it took them 3 hours.

Step 1)

Add both speeds. 20km+80km=100km

Step 2)

Total distance between them = 300km

So do 300km/100km = 3hours.

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The solution is: .

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Hope this helped!

4 0

3 years ago

Sketch these cartesin products on the x-y plane R^2 14. 11,21x1,1.5,2

ale4655 [162]

Answer:

$\left\{11, 21\right\} \times \left\{1, 1.5, 2\right\} = \left\{ (11, 1), (11, 1.5), (11, 2), (21, 1), (21, 1.5), (21, 2)\right\}$

Step-by-step explanation:

The Cartesian product between two discrete sets, is given by all possible ordered pairs originated with the combinations of the elements of the two sets, thus the requested Cartesian product is:

$\left\{11, 21\right\} \times \left\{1, 1.5, 2\right\} = \left\{ (11, 1), (11, 1.5), (11, 2), (21, 1), (21, 1.5), (21, 2)\right\}$

$A = (11, 1)\\B = (11, 1.5)\\C = (11, 2)\\D = (21, 1)\\E = (21, 1.5)\\F = (21, 2)\\$

You can see the attached file

Download pdf

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3 years ago

Match the system of equations on the left with the appropriate solution on the right.

tia_tia [17]

Number one would be no solution

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3 years ago

A delivery company purchased a new delivery truck for $43,200. The depreciated value of the truck can be estimated by the number

nasty-shy [4]

Answer:

$f(t)=43,200-7200t$

Step-by-step explanation:

We have been given that a delivery company purchased a new delivery truck for $43,200. The depreciated value of the truck can be estimated by the number of t years in service. The truck depreciates at a rate of $7,200 per year.

This means that after t years truck will depreciate 7200t. To find the truck's depreciated value after t years we will subtract 7200t from the cost of new delivery truck (43,200).

$f(t)=43,200-7200t$

Therefore, the function $f(t)=43,200-7200t$ could be used to estimate the truck's depreciated value after t years.

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3 years ago