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nikitadnepr [17]
3 years ago
15

Which angles are alternate exterior angles with angle 11?

Mathematics
1 answer:
Elena-2011 [213]3 years ago
8 0

The above questions answer is 8 and 14

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57 divided by 858 worked
Vesnalui [34]

Answer:

  0.0\overline{664335}

Step-by-step explanation:

The attachment shows the working, and it shows the problem repeats itself every 6 digits of quotient.

7 0
3 years ago
An event manager recorded the number of people in different age groups that attended a music concert.
Misha Larkins [42]

Answer:

the third picture on the bottom with the bars.

Step-by-step explanation:

Histograms use bars to show values.

7 0
3 years ago
I need to know the points of T and how to get it
german

Answer: (-2, -2)

Step-by-step explanation:

When you approach these types of questions, first look for a pattern. Both the x and y value are divided by 2.5 in the image, so do the same with point t. The image would be -5/2.5, -5,2.5 or -2, -2

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2 years ago
Help me plz fast and I will mark the brainiest
Natasha_Volkova [10]

Answer:

a is the answer -3

Step-by-step explanation:

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have a nice day

6 0
3 years ago
A group of retired admirals, generals, and other senior military leaders, recently published a report, "Too Fat to Fight". The r
weqwewe [10]

Answer:

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

Step-by-step explanation:

1) Data given and notation  

n=180 represent the random sample taken  

X=125 represent the number of americans between 17 to 24 that not qualify for the military

\hat p=\frac{125}{180}=0.694 estimated proportion of americans between 17 to 24 that not qualify for the military

p_o=0.75 is the value that we want to test  

\alpha=0.05 represent the significance level  

Confidence=95% or 0.95  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that less than 75% of Americans between the ages of 17 to 24 do not qualify for the military :  

Null hypothesis: p\geq 0.75  

Alternative hypothesis:p < 0.75  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.  

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

6 0
3 years ago
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