Answer:
values of q are q=0,-9,5/6
Option B is correct
Step-by-step explanation:
We need to solve the equation:
2q(q+9)^2(6q-5)=0
We will be using zero factor polynomial i,e if ab=0 then a=0 and b=0
so, 2q(q+9)^2(6q-5)=0
2q =0, (q+9)^2 =0 and (6q-5)=0
Finding values of q
2q = 0 => q=0
(q+9)^2 =0 => taking square root
q+9 = 0
q = -9
(6q-5)=0 => 6q-5=0
6q = 5
q = 5/6
So, values of q are q=0,-9,5/6
Option B is correct
Answer:
-4
Step-by-step explanation:
plug in 2 for the x, plug in the -5 for the y which will give you the equation 3(2)+2(-5)=
3 x 2 is 6
2 x -5 is -10
then you will have 6 - 10
and your answer is -4
Simplify the radical by breaking the radicand up into a product of known factors.
Therefore the answer would be 2! Hopefully this helps.
I believe it’s X=+15 sorry if I’m wrong