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3 years ago

Find the surface area plz

Mathematics

1 answer:

vladimir1956 [14]3 years ago

7 0

Hi again! ;)

If we want to find the surface area of a cube, we need to find the area of one surface first, and then multiply that by 9, since there are 9 sides/surfaces on a cube.

Since each side of a square is the same, we first find the area of one surface:

9 × 9 = 81

Then, to find the surface area, we multiply 81 by 6:

81 × 6 = 486

The surface area is
$486 \: {in}^{2}$

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Part A If their food and beverages cost $25.30 and there is an 8% meals tax, how much is the bill? (Find the 8% tax then add it

dmitriy555 [2]

Answer:

Step-by-step explanation:

Tax

Meal plus tax = 25.3 + 8/100 * 25.3

Meal plus tax = 25.3 + 2.024 Round later. Find the total.

Meal plus tax = 27.324

Meal plus tax = 27.32 rounded to the nearest cent.

Tip

Total cost = 27.324 + 27.324 * 18 /100

Total cost = 4.91832 + 27.324

Total cost = 32.242

Rounded to nearest cent = 32.24 You should always round at the last step.

3 0

3 years ago

Will someone help me work through this problem, please

Ainat [17]

Step-by-step explanation:

Radius (r) = 2 ft

V = 4/3 × 22/7 × (2)³

= 4/3 × 22/7 × 8

= 33.52 ft³

6 0

3 years ago

What is the value for f(x)= 3^2x+1 when x =1/2

Papessa [141]

Taking 2x is power of 3.

So it will be like 3^(2*1/2) + 1
You are replacing 'x' with 1/2
and the equation becomes 3^1+1
So, f(1/2) = 4
Answer is 4.

If its like
3^(2x+1)
Then its like 3^[(2*1/2) +1]
It becomes 3^(1+1) = 3^2 = 9
So, the answer is 9

8 0

3 years ago

Find five consecutive integers such that: "the sum of the first and 4 times the third is equal to 60 less than 3 times the sum o

Monica [59]

Consecutive integers are integers that come one after another in order. For example, 2, 3, and 4 are all consecutive integers, as well as 100, 101, and 102. In general, if we have some integer n, the consecutive integers following it will be n + 1, n + 2, n + 3, etc. Here, we have five. If we

Call the first integer n,
Then the second integer will be n + 1,
The third will be n + 2,
The fourth will be n + 3,
And the fifth will be n + 4.

Now, let's break down the equation in English. We'll use #1, #2, #3, #4, and #5 as stand-ins for the five integers just so we can get things set up, then we'll replace them with the expressions we came up with in the first part. Starting from the beginning of the statement, let's translate words to symbols:

"The sum of the first and 4 times the third" → #1 + 4 × #3
"is equal to" → = (maybe obvious, but still!)
"60 less than 3 times the sum of the second, fourth, and fifth" → 3 × (#2 + #4 + #5) - 60

Putting that all together, we get the equation

#1 + 4 × #3 = 3 × (#2 + #4 + #5) - 60.

Replacing our stand-ins for the expressions we came up with, it becomes

n + 4(n + 2) = 3[(n + 1) + (n + 3) + (n + 4)] - 60

We can now start to simplify our equation to find n (the first integer) and the rest will follow easily from that. I'll start by focusing on the left side. We can distribute and combine like terms like so:

n + 4(n+2) = n + 4n + 8 = 5n + 8

Dealing with the right, we can get rid of some redundant parentheses and carry out the same process:

3[(n + 1) + (n + 3) + (n + 4)] - 60 = 3(n + 1 + n + 3 + n + 4) - 60

= 3(3n + 8) - 60 = 9n + 24 - 60 = 9n - 36

Our simplified equation now becomes

5n + 8 = 9n - 36.

Subtracting 5n from either side:

8 = 4n - 36

Adding 36 to either side:

44 = 4n

And dividing either side by 4:

11 = n.

We now know that our first integer is 11, which means that our 5 consecutive integers are 11, 12, 13, 14, and 15.

7 0

3 years ago

Value of the derivative of g(x)=8-10Cosx at 'x=0' is?

VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Pre-Calculus

Unit Circle

Calculus

Derivatives
Derivative Notation
The derivative of a constant is equal to 0
Derivative Property: $\frac{d}{dx} [cf(x)] = c \cdot f'(x)$
Trig Derivative: $\frac{d}{dx} [cos(x)] = -sin(x)$

Step-by-step explanation:

Step 1: Define

g(x) = 8 - 10cos(x)

x = 0

Step 2: Differentiate

Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
Simplify Derivative: g'(x) = 10sin(x)

Step 3: Evaluate

Substitute in x: g'(0) = 10sin(0)
Evaluate Trig: g'(0) = 10(0)
Multiply: g'(0) = 0

3 0

3 years ago