To find the area of a quarter circle, you simply take a quarter of a full circle. As all quarters are equal, this means that the formula would be <span><span>π<span><span>r2</span>4</span></span><span>π<span><span>r2</span>4</span></span></span><span>. But wait, there's more. If you notice, </span><span><span>π<span><span>r2</span>4</span>=π<span><span>r2</span>2</span></span><span>π<span><span>r2</span>4</span>=π<span><span>r2</span>2</span></span></span><span>. This coincides with the circle formula, just with half the radius. Notice anything? A quarter of a circle can be calculated in the same way a circle a quarter the size can. This means that a quarter circle is equal to a circle a quarter size. In this same way, a ninth of a circle is equal to a circle of one ninth the size.</span>
The range of the given function is represented by {-6,-4,2}.
<h3>Domain and Range</h3>
The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined.
While the domain is related to the values of x, the range is related to the possible values of y that the function can have.
Here, you need to replace the given domain values in the equation: f(x)=x-4. The question gives that the domain is represented by: -2 ,0 ,2 .
Thus,
For x=-2, you have:
f(x)= x-4
f(x)= -2-4
f(x)= -6
For x=0, you have:
f(x)= 0-4
f(x)= 0-4
f(x)= -4
For x=2, you have:
f(x)= x-4
f(x)= 2-4
f(x)= -2
Therefore, the range of the given function is {-6,-4,2}
Learn more about the range here:
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The answer to your problem is -2.1.
