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3 years ago

Two parallel lines are crossed by a transversal. What is the value of D?

Mathematics

2 answers:

Scrat [10]3 years ago

8 0

Answer:

The correct option is 3.

Step-by-step explanation:

Given information: Lines r and s are parallel to each other.

If two lines intersect each other at a point then the opposite angles are called vertically opposite angles and these vertically opposite angles are always same.

From the given figure it is clear that the angle having measure d° and angle having measure 125° are vertically opposite angles. So,

$d^{\circ}=125^{\circ}$ (Vertically opposite angles)

$d=125^{\circ}$

The value of d is 125, therefore the correct option is 3.

Sliva [168]3 years ago

4 0

Answer:c

Step-by-step explanation:

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If the typical balance on Lucy's credit card is $650 and the interest rate (APR) on her credit card is 18%, how much in interest

Mariana [72]

$9.75

<h3>Further explanation </h3>

Given:

The typical balance on Lucy's credit card is $650.
The interest rate (APR) on her credit card is 18%.

Question:

How much in interest would you expect Lucy to be charged in a typical month?

The Process:

This problem includes the type of determining simple interest.

$\boxed{ \ I = P \times r \times t \ }$

where,

I = simple interest
P = principal (initial amount)
r = annual interest rate
t = time (in years)

This time we will find out how much in interest we would expect to be charged in a typical month.

The data is as follows:

P = 650
r = 18% or $\frac{18}{100}$ or 0.18
t = $\frac{1}{12}$ year (one month)

Let us calculate how much in interest we would expect to be charged in a typical month.

$\boxed{ \ = 650 \times \frac{18}{100} \times \frac{1}{12} \ }$

$\boxed{ \ = 65 \times \frac{3}{10} \times \frac{1}{2} \ }$

$\boxed{ \ = \frac{195}{10} \times \frac{1}{2} \ }$

$\boxed{ \ = \frac{97.5}{10} \ }$

$\boxed{ \ = \frac{975}{100} \ }$

Thus the amount of interest we would expect Lucy to be charged in a typical month is $ 9.75.

_ _ _ _ _ _ _ _ _ _

Notes

We must be able to distinguish between simple and compound interest. Please learn about this in the link attached below.

<h3>Learn more </h3>

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