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rosijanka [135]

4 years ago

11

-3 times b is smaller than -33

1 answer:

Usimov [2.4K]4 years ago

3 0

Answer:

l think so because -3 if you add a 0 (-30) its smaller than -33

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Solve this system:<br><br> 2x+5y+z=3<br> x-3y+2z=2<br> -x+2y-3z=-7

12345 [234]

Answer:

x= -3

y= 1

z= 4

Step-by-step explanation:

Please see the attached pictures for the full solution.

*I evaluated the determinants using Sarrus' rule (see last picture):

∆= aei +bfg +cdh -gec -hfa -idb

*The symbol '∆' (delta) is usually used to denote a determinant.

4 0

4 years ago

A sled dog racer completed a race in 6 hours. Because of changes in the terrain, his average speed for the last 48 miles was twi

Serga [27]

A sled dog racer completed a race in 6 hours. Because of changes in the terrain, his average speed for the last 48 miles was twice as fast as his average speed for the first 12 miles. Which equation can be used to find r, his average speed in miles per hour, during the first 12 miles?

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3 years ago

Find the coordinates of the midpoint M and the distance between P(-6, -1) and Q(1,2). Round to the nearest

nlexa [21]

Answer:

M(-3.5, 0.5)

Step-by-step explanation:

<u>Given points:</u>

P(-6, -1) and Q(1,2)

<u>Midpoint by using midpoint formula:</u>

x = (-6 + 1)/2 = -3.5
y = (-1 + 2)/2 = 0.5
M(-3.5, 0.5)

4 0

3 years ago

in a section of a baseball stadium, there are 11 seats in the first row. there are 15 seats in the second row, 19 seats in the t

Sever21 [200]

I believe the answer is A

3 0

4 years ago

Read 2 more answers

Total freshman = 58. Number of freshman who prefer cheese toppings= 14. Determined the probability that a freshman prefer cheese

Yakvenalex [24]

Answer:

The probability that a freshman prefer cheese toppings is 0.241

Step-by-step explanation:

Probability of any event E = $\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}$

Here, let E : Event of choosing cheese toppings

So, the number of favorable outcomes = 14

Total number of outcomes = 58

So, $P(E) = \frac{\textrm{Number of students who like cheese toppings}}{\textrm{Total number of students}}$

or, P(E) = $\frac{14}{58} = 0.241379$

So,the probability that a freshman prefer cheese toppings is 0.241379

Rounding of 0.241379 to the <u>nearest thousandth</u>, we get

Here , in 0.241379 thousandth digit is 3, and 3 < 5,

so the value of P(E) = 0.241

4 0

3 years ago