Question

19. 2x²+5√3 x+6 = 0​

Answer 1

Answer:

Step-by-step explanation:

2x²+5√3 x+6 = 0​

Comparing this with quadratic equation ax^2+bx+c=0

So a=2,b=5√3,c=6

Discriminant D=b^2-4ac

D=(5√3)^2-4.2.6

= 75-48

=27.

27 >0

Hence the roots are real roots

X=(-b+√D)/2a, Y=(-b-√D)/2a

X=(-5√3+√27)/2×2, Y=(-5√3-√27)/2×2

X=(-5√3+3√3)/4,. Y=(-5√3-3√3) /4

X=-2√3/4,. Y=-8√3/4

X=-√3/2, Y =-2√3

So roots are X=-√3/2,Y=-2√3