Answer:
Step-by-step explanation:
2x²+5√3 x+6 = 0
Comparing this with quadratic equation ax^2+bx+c=0
So a=2,b=5√3,c=6
Discriminant D=b^2-4ac
D=(5√3)^2-4.2.6
= 75-48
=27.
27 >0
Hence the roots are real roots
X=(-b+√D)/2a, Y=(-b-√D)/2a
X=(-5√3+√27)/2×2, Y=(-5√3-√27)/2×2
X=(-5√3+3√3)/4,. Y=(-5√3-3√3) /4
X=-2√3/4,. Y=-8√3/4
X=-√3/2, Y =-2√3
So roots are X=-√3/2,Y=-2√3
