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3 years ago

19. 2x²+5√3 x+6 = 0

Mathematics

1 answer:

Mama L [17]3 years ago

7 0

Answer:

Step-by-step explanation:

2x²+5√3 x+6 = 0

Comparing this with quadratic equation ax^2+bx+c=0

So a=2,b=5√3,c=6

Discriminant D=b^2-4ac

D=(5√3)^2-4.2.6

= 75-48

=27.

27 >0

Hence the roots are real roots

X=(-b+√D)/2a, Y=(-b-√D)/2a

X=(-5√3+√27)/2×2, Y=(-5√3-√27)/2×2

X=(-5√3+3√3)/4,. Y=(-5√3-3√3) /4

X=-2√3/4,. Y=-8√3/4

X=-√3/2, Y =-2√3

So roots are X=-√3/2,Y=-2√3

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lukranit [14]

Answer:

Step-by-step explanation:

The y-coordinate of the point where both lines intersect will give us the same solution for x.

At y = 4, both equations will have a corresponding x-value of 1.

Therefore, the value of y that that will make both equations have the same solution of x is 4.

7 0

3 years ago

Solve for the variable c in this equation a(c + b) = d

noname [10]

Multiply everything in the parenthesis by a.

ac + ab = d

Subtract ab from both sides.

ac = d - ab

Divide a on both sides.

c = d - ab / a

Hope this helps!

3 0

3 years ago

A Ski resort tracks the proportion of seasonal employees who are rehired each season. Rehiring a seasonal employee is beneficial

DaniilM [7]

The test statistic z will be equal to -0.946 and it shows that there is no significant difference in the proportion of rehires between full time and part time.

Given sample sizes of 833 and 386 and result of samples 434 and 189.

$n_{1} =833, n_{2}=386$

Proportion of full time=434/833=0.52

Proportion of part time=189/386=0.49.

Difference in proportion =0.52-0.49

$H_{0}:$ TTF- i∈ rho=0

$H_{1}:$ TTF+i∈ rho≠0.

Mean of difference=0.03

Z=(X-μ)/σ

σ= $\sqrt{0.4517/447}$

=0.0317

σ=0.0317

z=(0-0.03)/0.0317

=-0.03/0.0317

=-0.317

p value will be =0.1736.

Because p value is greater than 0.01 so we will accept the null hypothesis which shows that there is no significant difference in the proportions.

Hence there is no significant difference in the proportion of rehires between full time and part time.

Learn more about z test at brainly.com/question/14453510

#SPJ4

6 0

2 years ago

Can anyone help me solve this

yawa3891 [41]

Answer:

a. $45.54; b. $51.42; c. See below

Step-by-step explanation:

a. 193 min

Service charge = $40.00

1st 100 min @ 0.021 = 2.10

Next 93 min @0.037 = 3.44

Total = $45.54

b. 317 min

Service charge = $40.00

1st 100 min @ 0.021 = 2.10

2nd 100 min @ 0.037 = 3.70

117 min @ 0.048 = 5.62

Total = $51.42

c. Piecewise function

The charge is

$40.00 + 0.021t if t ≤ 100
$42.10 + 0.037(t - 100) if 100 < t ≤ 200
$45.80 + 0.048 (t - 200) if t > 200

which we can write like this:

$f(t) =\begin{cases}40.00 + 0.021t & t \leq 100\\42.10 + 0.037(t-100) & 100 < t \leq200\\45.80 + 0.048(t-200) & t > 200\end{cases}$

5 0

3 years ago

7(2 + 3) − 4 · 2 2 the second two is up in the air fyi

AfilCa [17]

Answer:

Step-by-step explanation:

7(2 + 3) − 4 · 2² ← like that right so

parenthesis first add the numbers up↓

7(5) - 4 · 2²

write number in exponential form↓

7(5) - 2²· 2²

multiply↓

35 - 2² · 2²

calculate the product↓

35 - 2⁴

evaluate the power↓

35-16

then subtract↓

7 0

2 years ago

19. 2x²+5√3 x+6 = 0​

19. 2x²+5√3 x+6 = 0