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ZanzabumX [31]
3 years ago
10

You went to Walmart and spend $75. Of the total bill, $45.50 included non-taxable items. How much is the final bill if you apply

a 7.5% tax to the taxable items?
Mathematics
1 answer:
Alina [70]3 years ago
5 0

We have been given that you went to Walmart and spend $75. Of the total bill, $45.50 included non-taxable items.

Let us find the amount of taxable items by subtracting amount of non-taxable items from total bill.

\text{Amount of taxable items}=\$75-\$45.50

\text{Amount of taxable items}=\$29.50

We have been given that the rate of tax is 7.5% to the taxable items. To find the amount of tax, we will find 7.5% of $29.50.

\text{Amount of tax}=\$25.50\times \frac{7.5}{100}

\text{Amount of tax}=\$25.50\times 0.075

\text{Amount of tax}=\$2.2125  

Final amount of bill would be amount of bill plus amount of tax.

\text{Final amount of bill}=\$75+\$2.2125

\text{Final amount of bill}=\$77.2125

Therefore, final amount of bill would be \$77.2125.

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Step-by-step explanation:

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if X=10 then, 15 times 10 plus 90 = 240.

Since the number of people must be under 240, there must be less than 10 seats in each row on the floor.

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Which value of x make the open sentence true? 2x – 3 = 15
Ksju [112]
2x - 3 = 15
2x = 15 + 3 = 18
x = 18/2 = 9

Therefore, the equired value of x is 9.
8 0
3 years ago
1. The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 800 v
Free_Kalibri [48]

Answer:

See step by step explanation

Step-by-step explanation:

Sample size   n  =  800

p₁  =  71 %      p₁ = 0,71     and  q₁ = 0,29

Claim from political strategy wants evaluation to see if that sample implies that residents who favor the construction are more than 68 %

Then  

p₀   =  68%      p₀ = 0,68

Sample size  800 big enough to use the approximation of binomial distribution to normal distribution

1) Hypothesis Test

Null Hypothesis                                  H₀          p₁  =  p₀

Alternative Hypothesis                      Hₐ          p₁  >  p₀

2)Test Statistics  z (s)

z(s)   =  (  p₁  -  p₀ ) / √p₁*q₁/n

z(s)   =  0,03 / √0,71*0,29/800

z(s)   =  0,03 /  0,016

z(s)  =  1,875

3) In the problem statement the expression " more than " has to be formulated in the alternative hypothesis and indicates that the test is one tail test to the right

4)  z(s)  =  1.875  from  z-Table we get  p-value  = 0,030

Now significance level is α  = 0,02

Therefore  p-value > 0.02

Then that value corresponds to the acceptance region for H₀.

We don´t have enough evidence to support the strategist´s claim

5) The level of significance is α = 0,02

6) If now we change  α to be equal to 0,01   α = 0,01

p-value > 0,01 and still we have to accept H₀

7) We accept H₀  we are not able to support strategist´s claim    

6 0
2 years ago
Match the width with the go given area.
LekaFEV [45]

Hello!

<h2>Answer:</h2>

\boxed{ \bf 1.~l~=~9.25~cm;~A~=~55.5~cm^2~matches~with~the~last~option~w~=~6~cm.}

\boxed{ \bf 2.~l~=~7.5~cm;~A~=~48.75~cm^2~matches~with~the~second~option~w~=~6.5~cm.}

\boxed{ \bf 3.~l~=~5~cm;~A~=~44~cm^2~matches~with~the~third~option~w~=~8.8~cm.}

\boxed{ \bf 4.~l~=~5~cm;~A~=~31.25~cm^2~matches~with~the~first~option~w~=~6.25~cm.}

<h2>__________________________________</h2><h2>Explanation:</h2>

We already know that the formula for area of a rectangle is A = l × w.

Notice how the width and the length are being multiplied to find the area.

Well, to find the width, we must do the <em>opposite</em> of multiplication, which is division.

Since we already have the length, all we have to do is divide the area by the length for each of the questions.

1:

A = l × w

55.5 = 9.25 × w

\frac{55.5}{9.25} = 6

2:

A = l × w

48.75 = 7.5 × w

\frac{48.75}{7.5} = 6.5

3:

A = l × w

44 = 5 × w

\frac{44}{5} = 8.8

4:

A = l × w

31.25 = 5 × w

\frac{31.25}{5} = 6.25

8 0
2 years ago
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