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Elina [12.6K]
2 years ago
15

Please say the answer of this 3√5+√5

Mathematics
2 answers:
Firlakuza [10]2 years ago
7 0

4√5

According to Brainly I need to have at least 20 characters before being able to 'Add My Answer'.

lina2011 [118]2 years ago
5 0

question;

3√5+√5

answer:

Decimal Form:

8.94427191

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Find the measure of each angle indicated.
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51

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What is the correct method of recording numerical information from an experiment?
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The correct method for recording numerical information from an experiment is the quantitative method.

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This method represents the way of recording that tracks variables (sometimes more than one) and how they interact with each other. This will help to establish relationship within your experiment.

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What expression can represent 4 more than the product of 6 and 2 1/2
mrs_skeptik [129]

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6 x 2 1/2 + 4 ??? I hope this is correct :)

Step-by-step explanation:

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7 0
3 years ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
2 years ago
Find the solution<br> x/5 - 1/5 = x/3 + 1/4
Vilka [71]

Answer:

x = - 27/8

x=-3\frac{3}{8}

Step-by-step explanation:

¹²⁾x/5 - ¹²⁾1/5 = ²⁰⁾x/3 + ¹⁵⁾1/4

12x - 12 = 20x + 15

- 12 - 15 = 20x - 12x

- 27 = 8x

x = - 27/8

x=-3\frac{3}{8}

4 0
3 years ago
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