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elena-s [515]
3 years ago
7

I need help with this question​

Mathematics
1 answer:
netineya [11]3 years ago
6 0

Answer:

i don't know i'm sorry dude i mean i just don't know but i love to help but i can't sorry

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Jules tosses a penny 3 times. List all the possible combinations of heads (H) and tails (T) that Jules might get.
pantera1 [17]
The number of combinations are 9. Its really simple, just do 3 x 3 = 9
3 0
3 years ago
Read 2 more answers
Would appreciate help!!
Artemon [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
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I NEED HELP ASAP
drek231 [11]

Answer:

80 / 5 = <u>40</u> / 5 + <u>40</u> / 5 = <u>10</u> + 6 = <u>16</u>

Step-by-step explanation:

80 / 5 = 16

__ / 5 + __ / 5

You can do 80 / 2 to fill in those two blanks because the answer needs to equal the same as 80 / 5

80 / 2 = 40

40 / 5 + 40 / 5

8 + 8 = 16

the third blank needs to also equal 16. So you can do 16 - 6 to know what fills in the blank.

16-6

10

10+6 = 16

The last blank must equal the same as all the other equations so 16 would fill it.

If you need further help, don't be afraid to reach out with any questions. I hope this helps!

3 0
3 years ago
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What two positive real numbers whose product is 21 have the smallest possible​ sum?
GalinKa [24]

Answer:

x=\sqrt{21}

y=\sqrt{21}

Step-by-step explanation:

Let x  and y are the two positive real numbers

product of two numbers is 21

x y=21

y=\frac{21}{x}

The sum of the two numbers is f(x) =x+y

Replace y with 21/x

f(x) =x+\frac{21}{x}

we need to find smallest possible sum , so we take derivative using power rule

f'(x)= 1-\frac{21}{x^2}

when sum is minimum then the derivative is equal to 0

0= 1-\frac{21}{x^2}

0=\frac{x^2-21}{x^2}

multiply both sides by x^2

x^2-21=0

x^2=21

Take square root on both sides

x=\sqrt{21}

y=\frac{21}{x}

y=\frac{21}{\sqrt{21}}

y=\sqrt{21}

3 0
4 years ago
Can someone helpppp meee?!!!:))
Slav-nsk [51]

Answer:

3(x+6)=3x+18 = infinite

x-7=-7+x = infinite

5(x-3)=15+5x = no solution

5 0
3 years ago
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