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shtirl [24]
3 years ago
8

A rectangle has a length of x and a width of 4 inches more than the length

Mathematics
1 answer:
irina [24]3 years ago
6 0
Width = 4x
You haven’t provided enough data, but lets say length (x) = 5
Then do the following:
Width = 4x
= 4 x 5
= 20
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Give me an example of an irrational number that is greater than 10
Pavel [41]

To find:

An irrational number that is greater than 10.

Solution:

Irritation number: It cannot be expression in the form of \dfrac{p}{q}, where, q\neq 0, p,q are integers.

For example: \sqrt{2}\sqrt{3},\pi, 1.263689...,etc..

We know that square of 10 is 100. So, square root of any prime number is  an example of an irrational number that is greater than 10.

First prime number after 100 is 101.

Required irrational number =\sqrt{101}

Therefore, \sqrt{101} is an irrational number that is greater than 10.

5 0
4 years ago
the larger of two number is 15 more than three times the smaller number. If the sum of the two numbers is 63, find tge numbers.
irakobra [83]
X is the smaller number. 3x + 15 is the larger number. So x + 3x + 15 = 63. 4x + 15 = 63.
4x = 48. x = 12. (Smaller number) The larger 36 + 15 or 51.
6 0
4 years ago
Read 2 more answers
Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y
vladimir2022 [97]

Answer:

No, She did not use the distributive property correctly.

Step-by-step explanation:

While multiplying (3-6y^2)(y^2+2), he did not use distributive property correctly. She only multiplied 3 with y^2 and not with 2. Also she multiplied -6y^2only with 2 and not with y^2.

6 0
3 years ago
The table lists how poverty level income cutoffs​ (in dollars) for a family of four have changed over time. Use the midpoint for
frez [133]

The poverty level cutoff in 1987 to the nearest dollar  was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: \mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right).

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar  was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0
2 years ago
Jennifer is building a square cage for her
stich3 [128]

Each side of the cage is 2x+4 and there are 4 sides.

This means 4(2x+4) which is equal to 8x+16, the answer is <u>B</u>

8 0
4 years ago
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