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2 years ago

Question 9 Multiple Choice Worth 1 points)

Mathematics

1 answer:

beks73 [17]2 years ago

8 0

Answer: $\bold{10 = \sqrt {\left( {x- 8 } \right)^2 + \left( {y - 9 } \right)^2 }}$

Step-by-step explanation:

<u>Given:</u>

The coordinates of Point A: (8, 9)

The coordinates of Point B are unknown: (x, y)

The distance from A to B is 10 units

Then, using the distance formula:

$AB = \sqrt {\left( {x- 8 } \right)^2 + \left( {y - 9 } \right)^2 }$

Therefore,

$10 = \sqrt {\left( {x- 8 } \right)^2 + \left( {y - 9 } \right)^2 }$

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Answer:

$240 {}^{}$

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3 years ago

The sea ice area around the North Pole fluctuates between about 6 million square kilometers in September to 14 million square ki

Aleksandr [31]

Answer:

there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

Step-by-step explanation:

Given the data in the question;

Let S(t) represent the amount sea ice around the North Pole in millions of square meters at a given time t,

t is the number of months since January.

Now, we use a cosine curve to model this scenario

Vertical shift will be;

D = ( 6 + 14 ) / 2 = 20 / 2

D = 10

Next is the Amplitude;

|A| = ( 6 - 14 ) / 2

|A| = 4

Now, the horizontal stretch factor will be;

B = 2π / 12

B = π/6

Hence;

S(t) = 4cos( π/6 × t ) + 10 ----------- let this be equation 1

Now we find when there will be less than 9 million square meters of sea ice;

S(t) = 9

so we have

9 = 4cos( π/6 × (t-2) ) + 10

9 - 10 = 4cos( π/6 × (t-2) )

-1 = 4cos( π/6 × (t-2) )

-1/4 = cos( π/6 × (t-2) )

so we have;

cos⁻¹( -1/4 ) = π/6 × (t₁-2) -------- let this be equation 2

2π - cos⁻¹( -1/4 ) = π/6 × (t₂-2) -------- let this be equation 3

so we solve equation 2 and 3

we have'

t₁ - t₂ = 6/π × ( 2π - cos⁻¹( -1/4 ) - cos⁻¹( -1/4 ) )

t₁ - t₂ = 6/π × ( 2π - 2cos⁻¹( -1/4 )

t₁ - t₂ = 6/π × ( π - cos⁻¹( -1/4 )

t₁ - t₂ = 6/π × ( π - 104.4775 )

t₁ - t₂ = 5.035

therefore, there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

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Wait can you draw diagrams on here?

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3 years ago

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Answer:

10 by 10 meters

Step-by-step explanation:

In calculus terms, you can use the formula for the perimeter which is 2l + 2w, and the area l × w.

Then since the area is 100

l × w = 100. So w = 100/l

Then substitute this into the perimeter formula.

w = 100/l → 2l + 2(w) = 2l + 2(100/l) = 2l + 200/l.

Then take the derivative d/dx [take the derivative of a quantity with respect to x], by using a simpler method known as the power rule:

d/dx[x^n] = nx^n-1

so p = 2l + 200/l becomes p' = 2 - 200/l^2

Since the derivative of a constant is 0, to solve for l, set p' to 0

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Now that we know the length is 10, We can substitute the length in the original equation to find the width.

l = 10 → w = 100/l → w = 100/10, w = 10.

Therefore the perimeter of each rectangular pen is 40, with a length of 10 and width of 10.

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Answer:

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Step-by-step explanation:

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