Question

Blood is accelerated from rest to a speed of 33.0 cm/s in a distance of 1.73 cm by the left ventricle of the heart. Determine the magnitude of the acceleration a of the blood.

Answer 1

Answer -

$314.74$ $\frac{m}{s^2}$

Explanation

As per the equation of Newton's third law of motion we know that -  

 $V_f^2 - V_0^2 = 2aS$

where  

 $V_f$

is the final speed  

and  

 $V_0$

is the initial speed.  

a is the acceleration and S represents the speed.  

Given  

Final velocity  $= 33$

 

centimeter per second, Initial velocity is equal to zero and the distance traveled is equal to  

 $1.73$

centimeter

Now, substituting the values in above equation, we get -

$33^2 - 0 = 2 * a* 1.73\\a = 314.74$

 

meter per second square