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Yakvenalex [24]
4 years ago
6

Blood is accelerated from rest to a speed of 33.0 cm/s in a distance of 1.73 cm by the left ventricle of the heart. Determine th

e magnitude of the acceleration a of the blood.
Biology
1 answer:
Karo-lina-s [1.5K]4 years ago
3 0

Answer -

314.74 \frac{m}{s^2}

Explanation

As per the equation of Newton's third law of motion we know that -  

 V_f^2 - V_0^2 = 2aS

where  

 V_f

is the final speed  

and  

 V_0

is the initial speed.  

a is the acceleration and S represents the speed.  

Given  

Final velocity  = 33

 

centimeter per second, Initial velocity is equal to zero and the distance traveled is equal to  

 1.73

centimeter

Now, substituting the values in above equation, we get -

33^2 - 0 = 2 * a* 1.73\\a = 314.74

 

meter per second square

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