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zaharov [31]
3 years ago
6

Brainliest answer pls answer appropriately or i will report

Mathematics
2 answers:
tamaranim1 [39]3 years ago
5 0

Answer:

  • <em>30cm</em><em> </em><em>+</em><em>27cm</em><em> </em><em>=</em><em>57cm</em><em> </em>
  • <em>10cm</em><em> </em><em>+</em><em>6cm</em><em>=</em><em>16cm</em><em> </em>
  • <em>17cm</em><em> </em><em>+</em><em>8cm</em><em> </em><em>=</em><em>25cm</em>
  • <em>57cm</em><em>+</em><em>16cm</em><em>+</em><em>25cm</em><em> </em><em>=</em>
  • <em>50cm</em><em>+</em><em>10cm</em><em>+</em><em>20cm</em><em>=</em><em>80cm</em>
  • <em>7cm</em><em>+</em><em>6cm</em><em>+</em><em>5cm</em><em>=</em><em>18cm</em>
  • <em>80cm</em><em>+</em><em>18cm</em><em>=</em><em>98cm</em>
Gnom [1K]3 years ago
3 0

Answer:

2064cm²

Step-by-step explanation:

The total surface area of a shape is given by the area of each side. In this case 2 × the trapezium/trapezoid, 1 × the top side, 1 × the bottom side, 1 × the left slanted side and 1 × the right slanted side.

Let's start with the trapeziums/trapezoids. The formula for their area is \frac{1}{2}h(a+b). In this case, because there are 2, we can work them out at once without the \frac{1}{2}.

By substituting a with 6cm (the top length), b with 27cm (the bottom length), and h with 8cm (the height), the equation becomes 8(27+6) or 8×33, which can be solved to 264cm².

The rest of the sides are rectangles, which use the formula lw for area. For the top side, this is 6×30, or 180cm².

For the bottom side, this is 27×30, or 810cm².

For the left slanted side, this 10×30, or 300cm².

For the right slanted side, this is 17×30, or 510cm².

We should add these all together to get the final result. This equation is 264+180+810+300+510. This adds up to 2064cm².

**This content involves total surface area of prisms, which you may wish to revise. I'm always happy to help!

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Use the data set to determine which statements are correct. Check all that apply. 115, 120, 118, 104, 109, 148, 135, 141, 139 Th
Karo-lina-s [1.5K]

Question

Use the data set to determine which statements are correct. Check all that apply. 115, 120, 118, 104, 109, 148, 135, 141, 139

a)The median is 120.

b)The median is 109.

c)There is an outlier.

d) The lower quartile is 118.

e)The lower quartile is 112.

f)The upper quartile is 140.

g)The upper quartile is 141.

h))The interquartile range is 28.

Answer:

a)The median is 120.

e)The lower quartile is 112

f)The upper quartile is 140

h)The interquartile range is 28

Step-by-step explanation:

We are given the above Data sets:

115, 120, 118, 104, 109, 148, 135, 141, 139

To confirm the correct options, we have to find the median, lower and upper quartile and the interquartile range

115, 120, 118, 104, 109, 148, 135, 141, 139

We have to find rearrange this numbers from lowest to highest

Hence we have:

104, 109, 115, 118, 120, 135, 139, 141, 148

1) Median

104, 109, 115, 118, 120, 135, 139, 141, 148

The formula for median =

1/2(n + 1)th value

n = number of terms = 9

=1/2(9 + 1)th value

= 1/2(10)th value

= 5th value

The median is the 5th value = 120

Option a) is correct

2) Lower Quartile

The formula for lower quartile=

1/4(n + 1)th value

n = 9

= 1/4(9 + 1)th value

= 1/4(10)th value

= 2.5th value

This means the value is between the 2nd and 3rd values

109= 2nd value

115= 3rd value

First Quartile = 109+ 115/2

= 224/2

= 112

Therefore, Option e)The lower quartile is 112.

3)Upper Quartile

The formula for upper quartile=

3/4(n + 1)th value

n = 9

= 3/4(9 + 1)th value

= 3/4(10)th value

= 7.5th value

This means the value is between the 7th and 8th values

139= 7th value

141 = 8th value

First Quartile = 139 + 141/2

= 280/2

= 140

Therefore, option f)The upper quartile is 140 is correct.

4) The formula for Interquartile range is

Upper quartile - Lower quartile

= 140 - 112

= 28

Therefore, the option h)The interquartile range is 28 is correct.

Looking at the data set below, their is no outlier present.

104, 109, 115, 118, 120, 135, 139, 141, 148

Hence, c)There is an outlier is not correct.

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