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horrorfan [7]
2 years ago
6

A photo is 15 cm high and 9 cm wide Michael wants to but porcelain shrink it so it's height is 6 cm High how wide will it then b

e
Mathematics
1 answer:
weqwewe [10]2 years ago
3 0

Answer:

3.6cm

Step-by-step explanation:

Given data

We are given that the dimension of the photo is

Height= 15cm

Width= 9cm

That is

            15cm height  will make 9cm width

hence    6cm height will make x widht

cross multiply

9*6= 15*x

54= 15x

x= 54/15

x= 3.6cm

Hence the width will be 3.6cm

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Find the smallest number such that the remainder is 3 when it is divided by 16,20 or 24.​
schepotkina [342]

Answer: 123

Step-by-step explanation:

Foe us to solve this, we have to find the lowest common multiple of 16, 20 and 24 first and then add 3 to the LCM. This goes thus:

Multiples of 16 = 16, 32, 48, 64, 80, 96, 112, 128, 144, 160

Multiples of 20 = 20, 40, 60, 80, 10, 120, 140, 160

Multiples of 24 = 24, 48, 72, 96, 120

Therefore, the Lowe's common multiple is 120.

We then add the remainder of 3 and this will give:

= 120 + 3

= 123

4 0
2 years ago
Which shows all the prime factors for 72?
Ray Of Light [21]
C. 2-2-2-3-3 because they are all prime numbers. If you have another problem like this just use the prime number tree. Hope this helps
8 0
2 years ago
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Write in simple radical form:
WARRIOR [948]

Answer:

The answer to your question is \frac{2}{3}

Step-by-step explanation:

Here, there is a difference of squares, so just solve it and simplify

              ( 1 + \frac{1}{\sqrt{3} } ) (1 - \frac{1}{\sqrt{3} } )

Multiply the binomials

             = 1 - \frac{1}{3}

Simplify

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7 0
3 years ago
if Sandy ran 4 miles every week for 4 weeks, she would reach her goal of 20 miles for the month. the first day of the first week
Reika [66]
She would only run 16 miles a month
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3 years ago
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REALLY APPRECIATE YOUR HELP<br><br>Given log x = 3 and log y = 2, prove that x^2 -7xy =3000y​​
anyanavicka [17]

Answer:

if \:  log(x )  = 3 \\  log_{10}(x)  = 3 \\   {10}^{3}  = x \\ therfore \to \:  \boxed{x =  {10}^{3} } \\ \\  if \:  log(y )  = 2 \\  log_{10}(y)  = 2 \\   {10}^{2}  = y \\ therfore \to \:  \boxed{y=  {10}^{2} }

Step-by-step explanation:

x^2 -7xy =3000y \: then \to \\ x^2 =3000y + 7xy \\ {(10 ^{3} )}^{2}  = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{5} )   \\  {10}^{6}  = 300000 + 700000 \\   \boxed{{10}^{6}  = 1000000} \\ hence \: the \: equation \to \: x^2 -7xy =3000y \\ \boxed{ is \: corret}

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3 0
3 years ago
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