Question

Let AABC be a right triangle with mzC = 90°. Given tan 2B = 0.125, find tan 2A. tan ZA =

Answer 1

Answer:

Solution given:

In right angled triangle ABC

TanB=$\frac{AC}{BC}$

0.125×BC=AC

AC=0.125BC

now

TanA=$\frac{BC}{AC}$=$\frac{BC}{0.125BC}$=8° is your answer.

Answer 2

Answer:

• 8

Step-by-step explanation:

• tan = opposite leg / adjacent leg

Given

• tan ∠B = b/a = 0.125

Find tan ∠A

• tan ∠A = a/b = 1/ tan ∠B

Since tan ∠B = 0.125

• tan ∠A = 1/0.125 = 8