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stiv31 [10]
3 years ago
12

Find s(20) for the sequence s(n)=5n-2,ne {1 2, 3,... }

Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

Step-by-step explanation:

c

S(20)=

5*20-2=100-2=98

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What is the difference of the polynomials?
Vilka [71]

Answer:

8r^6s^3-5r^5s^4+r^4s^5+5r^3s^6

Step-by-step explanation:

We want to simplify;


(8r^6s^3-9r^5s^4+3r^4s^5)-(2r^4s^5-5r^3s^6-4r^5s^4)


We expand the bracket to obtain;


8r^6s^3-9r^5s^4+3r^4s^5-2r^4s^5+5r^3s^6+4r^5s^4


We now group the like terms to obtain;


8r^6s^3-9r^5s^4+4r^5s^4+3r^4s^5-2r^4s^5+5r^3s^6


We now simplify to get;

8r^6s^3-5r^5s^4+r^4s^5+5r^3s^6


The correct answer is C


3 0
3 years ago
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A circle is shown. Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W.
Marat540 [252]

<u>Given</u>:

Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W. Secant T V intersects the circle at point U.

The length of TU is (y - 2).

The length of UV is 8.

The length of SW is (y + 4)

The length of WV is 6.

We need to determine the length of line segment SV.

<u>Value of y:</u>

The value of y can be determined using the intersecting secant theorem.

Applying, the theorem, we get;

WV \times SV=UV \times TV

Substituting the values, we have;

6 \times (y+4+6)=8 \times (y-2+8)

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Thus, the value of y is 6.

<u>Length of SV:</u>

The length of SV is given by

SV=SW+WV

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SV=6+4+6

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Thus, the length of SV is 16 units.

Hence, Option D is the correct answer.

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<h3>Answer: Choice A is correct.</h3>

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Answer:

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