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Hoochie [10]
3 years ago
5

Which set of side lengths create a right triangle ?

Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:

(8, 15 and 17)

Step-by-step explanation:

\sqrt{10^{2} +28^{2} } \neq 29

\sqrt{6^{2} +8^{2} } \neq 13

\sqrt{7^{2} +12^{2} } \neq 14

\sqrt{8^{2} +15^{2} } =17

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it's easy to by them Cheaper tbh  with you  

and it's a quiz Right??

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3 years ago
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If there's a sale and the original price is 140 and it's one fifth off how much is the sale?
Alex777 [14]
$112
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4/5 x 140 =112
hope this helps :)
6 0
3 years ago
1854times845 could someone help me​
vivado [14]

Answer:

1,566,630

Step-by-step explanation:

1854*845=1,566,630

8 0
3 years ago
Can you pls help me with this it's about the immune system
slamgirl [31]

Answer:

A Fever is an Inmune system response.

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7 0
2 years ago
Suppose in the population, the Anger-Out score for men is two points higher than it is for women. The population variances for m
tatuchka [14]

Answer:

a)= 2

b) 6.324

c) P= 0.1217

Step-by-step explanation:

a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)

b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by

σ_X`1- X`2 = √σ²/n1 +σ²/n2

Var ( X`1- X`2) = Var X`1 + Var X`2 =  σ²/n1 +σ²/n2

so

σ_X`1- X`2 =√20 +20 = 6.324

if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.

Where as Z is normally distributed with mean zero and unit variance.

If we take X`1- X`2= 0 and u1-u2= 2  and standard deviation of the sampling distribution = 6.324 then

Z= 0-2/ 6.342= -0.31625

P(-0.31625<z<0)= 0.1217

The probability would be 0.1217

8 0
2 years ago
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