3 years ago

Solve for x round your answer and to the nearest tenth

Mathematics

1 answer:

kow [346]3 years ago

6 0

I think it's 24.8 i'm not sure tho

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2 years ago

49:05

lorasvet [3.4K]

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2 years ago

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Rom4ik [11]

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D. $\frac{4x^{2} \sqrt{29}}{29}$

Step-by-step explanation:

Given the expression:

$\frac{40x^{2} \sqrt{x^{12} } }{10x^{2} \sqrt{29x^{8} } }$

divide by the common factor to have;

$\frac{4\sqrt{x^{12} } }{\sqrt{29x^{8} } }$ = $\frac{4(x^{12}) ^{\frac{1}{2} } }{(29x^{8}) ^{\frac{1}{2} } }$

= $\frac{4x^{6} }{\sqrt{29}x^{4} }$

= $\frac{4x^{2} }{\sqrt{29} }$

Rationalize the denominator, we have;

$\frac{4x^{2} }{\sqrt{29} }$ x $\frac{\sqrt{29} }{\sqrt{29} }$

So that,

$\frac{4x^{2} \sqrt{29} }{29}$

Thus,

$\frac{40x^{2} \sqrt{x^{12} } }{10x^{2} \sqrt{29x^{8} } }$ = $\frac{4x^{2} \sqrt{29} }{29}$

The correct option is D.

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2 years ago