Answer:
The center of that class, which is the sum of its largest and smallest values divided by 2 ⇒ E
Step-by-step explanation:
* Lets explain what is the class mid-point
- It is defined as the average of the upper and lower class limits
- The class midpoint is the lower class limit plus the upper class limit
divided by 2
- The easiest way to find the class mid-point is to add the upper
and lower boundary and divide your answer by two
- The lower limit for every class is the smallest value in that class.
- The upper limit for every class is the greatest value in that class
* <u><em>Lets solve the problem</em></u>
- It is not the largest value of that class minus the class width
- Its not the difference between the largest and smallest values of
that class
- It is not the difference between the largest and smallest values of
that class divided by 2
- It is the center of that class, which is the sum of its largest and
smallest values divided by 2
The answer is B (20.2 ft)
Answer:
<em>least</em><em> </em><em>to</em><em> </em><em>greatest</em>
<em>.</em><em>86</em><em>,</em><em> </em><em>8</em><em>/</em><em>9</em><em>,</em><em> </em><em>.</em><em>9</em>
You're going to get a long decimal. Just divide 563 by 6, and you'll get about 93.83333333...
