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Gemiola [76]
3 years ago
9

How much money does an employee

Mathematics
1 answer:
Serga [27]3 years ago
8 0

Answer:

D. 4000 per month

Step-by-step explanation:

If they make 48000 per year, to find how mmuch s/he makes in a month, we have to divide it by 12 because there are 12 months in a year.

$48,000/12= $4000 per month

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Which scale factors produce an expansion under a dilation of the original image?
snow_lady [41]

Answer:

The correct answer is -8 and 7

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6 0
4 years ago
(m3 - 6m2 - 16m + 63) divided by (m - 7)
Arlecino [84]

Therefore( m^3 -6m^2-16m +63 )÷ (m-7)  =  (m^2 +m-9)

Step-by-step explanation:

m^3 -6m^2-16m +63

=m^3 -7m^2+m^2 -7m-9m+63

=  m^2(m-7)+m(m-7)-9(m-7)

= (m-7 ) (m^2 +m-9)

Therefore( m^3 -6m^2-16m +63 )÷ (m-7)  =  (m^2 +m-9)

3 0
4 years ago
Calculate the circumference of a circle when the diameter is 5cm. Give your answer to 2
FrozenT [24]

Answer:15.70

Step-by-step explanation:The formula for the circumference is 2πr. Plug-in the number provided into the formula, since diameter is double the radius you just divide the 5 by 2 to get 2.5.

So, 2π2.5=15.70

2 time π =6.28

6.28 time 2.5= 15.70

7 0
3 years ago
There were three quizzes for the week. The first quiz was worth twice as much as the second quiz. The third quiz was 10 points l
iren2701 [21]
X+y+z=70
x=2y
z=2y-10
6 0
3 years ago
quan and Krystal earned the same amount of points playing the same video game.Quan played for 45 minutes Krystal played for 30 m
yulyashka [42]

Answer:

The rate of Krystal is higher

Step-by-step explanation:

Assume that they earned P points in the game

then the rate of Quan = \frac{P}{45}

and the rate of Krystal = \frac{P}{30}

∵\frac{1}{30}>\frac{1}{45} (if two fractions have same numerator then the greatest fraction which has the smallest denominator)

∴ The rate of Krystal is higher than the rate of Quan

* To be sure let P = 90 as an example

The rate of Quan = 90/45 = 2 points per minute

The rate of Krystal = 90/30 = 3 points per minute

So the rate of Krystal is higher

7 0
3 years ago
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