Left 4 and up 1. x means left and right , y means up and down. x-4 would be left 4, y+1 would be up 1. :)
Answer:
The length of each red rod is 10 cm and the length of each blue rod is 14 cm
Step-by-step explanation:
Let
x ----> the length of each red rod in centimeters
y ----> the length of each blue rod in centimeters
we know that
----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system of equations is the intersection point both graphs
using a graphing tool
The solution is the point (10,14)
see the attached figure
therefore
The length of each red rod is 10 cm and the length of each blue rod is 14 cm
Any number 1-26 should work. the expression would me x<$26.
The solution of the given exponential equation is 0.688.
Given that Mike is working on solving the exponential equation 37ˣ = 12.
An exponential equation is an exponential equation where the power (or) part of the exponent is a variable.
firstly, we have to slve this equation is by converting it to logarithmic form. Any exponential equation can be transformed into an equivalent logarithmic equation as follows:
aˣ = y
logₐy = x
Now, we will apply this transformation to our equation and we get
log₃₇12=x
Further, we will apply the change of base formula so that solution is written in terms of base 10 logs:
x=log12/log37
So, this is an exact answer to given equation, but we can simplify it further by using decimal approximation of it using a calculator. Remember that these logs are base 10:
x≈1.079/1.568
x=0.688
Hence, the solution of the given exponential equation 37ˣ=12 is 0.688.
Learn more about exponential equation from here brainly.com/question/24162621
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Answer: See explanation
Step-by-step explanation:
You didn't give the expressions but here are some expressions
a. ✓4x²y^4. 1. 2x✓y
b. ✓8x²y. 2. 2y✓2x
c. ✓4x²y. 3. 2xy²
d. ✓16xy². 4. 2x✓2y
e. ✓8xy². 5. 4y✓x
a. ✓4x²y^4 = ✓4 × ✓x² × ✓y^4
= 2 × x × y²
= 2xy²
Therefore, ✓4x²y^4 = 2xy²
b. ✓8x²y = ✓8 × ✓x² × ✓y
= ✓4 × ✓2 × ✓x² × ✓y
= 2 × ✓2 × x × ✓y
= 2x✓2y
Therefore, ✓8x²y = 2x✓2y
c. ✓4x²y = ✓4 × ✓x² × ✓y
= 2 × x × ✓y
= 2x✓y
Therefore, ✓4x²y = 2x✓y
d. ✓16xy² = ✓16 × ✓x × ✓y²
= 4 × ✓x × y
= 4y✓x
Therefore, ✓16xy² = 4y✓x
e. ✓8xy² = ✓8 × ✓x × ✓y²
= ✓4 × ✓2 × ✓x × ✓y²
