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blsea [12.9K]
3 years ago
6

Please help ASAP thank youu!!

Mathematics
1 answer:
Gennadij [26K]3 years ago
4 0

Answer:

1. (-5)

Step-by-step explanation:

Here you go, glad to help :)

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. If (x + 2) is a fac
vitfil [10]
If x+2 is a factor of x^3+6x^2+kx+10, then if we replace x by -2 in the polynomial x^3-6x^2+kx+10, we must get zero:
x=-2→(-2)^3-6(-2)^2+k(-2)+10=0→
-8-6(4)-2k+10=0→
-8-24-2k+10=0
-2k-22=0
Solving for k. Adding 22 both sides of the equation:
-2k-22+22=0+22
-2k=22
Dividing both sides of the equation by -2:
-2k/(-2)=22/(-2)
k=-11

Answer: k = - 11
4 0
4 years ago
Solve 3m- 5h = 45 for h
Masja [62]

3m- 5h = 45\\5h=3m-45\ /:5\\h=\frac{3m-45}{5}\ \ \ or\ \ \ h=\frac{3}{5}m-9

4 0
3 years ago
Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
Sunny_sXe [5.5K]

Answer:

  1. -1392.09
  2. -1744.43
  3. -1636.41

Step-by-step explanation:

using the given integral

calculate:  Δx = (12-0) / 8 = 3/2

Xo = 0,   f(x) = x^3sin(x)

X1 = 3/2 ,   X2 = 3, X3 = 9/2,  X4 = 6,  X5 = 15/2,  X6 = 9,  X7 = 21/2,  X8 = 12

Inputting the given values into the Trapezoid rule, midpoint rule and Simpson's rule to approximate the given integral with the specified value of n = 8

8 0
3 years ago
Please help and explain! *Serious answers only* 30 points :)
topjm [15]
Ok so it's a proportion so this fraction is to this fraction. the smaller rectangle has sides 4 and 12. the larger one has 8 and x. so u set it up 4/12=8/x. the 4 and 8 r both the short sides so u want those on top and 12 and x r long sides so those on bottom. since that is not an answer option u can set it up as 8/4=x/12 because u still keep the variables of the same rectangle from being multipled with each other. so answer #2 is correct
4 0
4 years ago
Read 2 more answers
In an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin,
AleksandrR [38]

Answer:

Step-by-step explanation:

Given that in an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin, and a second group was given a placebo. A sample consisting of 50 women who received aspirin has mean arterial blood pressure 120mmHg and standard deviation 10mmHg; a sample of 42 women who were given the placebo has mean blood pressure 115mmHg and standard deviation 12mmHg.

Population variances are equal

H_0: \bar x = \bar y\\H_a: \bar x \neq \bar y

(two tailed test at 5% significance level)

Here x denotes group I and Y group II

                  N       Mean     StDev SE Mean

Sample 1   50     120      10  1.4142

Sample 2 42       115      12  1.8516

Pooled std deviation = 10.9565

df=80

Mean difference= 5

Test statistic t = mean diff/std error = \frac{5}{2.3299}=2.1803

p value = 0.0318

since p <0.05 we reject H0

b) We find p >0.01 hence at 1% significance level we accept H0

This implies that 99% confidence interval contains mean difference =0

4 0
4 years ago
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