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kramer
3 years ago
11

HELP DUE IN 5 MINUTES

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0

Answer:

hard

Step-by-step explanation:

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Explain how to estimate the square root of 1659
Nata [24]

Explanation:

Find the two closest square numbers to 1659.

40*40=1600

41*41=1681

Decide much closer to either 1600 or 1681 is 1659.

If it is exactly halfway between the two numbers, the square root is 40.5.

If it is closer to 1600, the sq rt decimal is between 1 and 4.

If it is closer to 1681, the sq rt decimal is between 6 and 9.

7 0
3 years ago
Please help! I thought I knew the full answer but I guess not.
Hitman42 [59]

\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{24})\qquad  (\stackrel{x_2}{7}~,~\stackrel{y_2}{-53}) \\\\\\ slope =  m\implies  \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-53-24}{7-(-4)}\implies \cfrac{-77}{7+4}\implies \cfrac{-77}{11}\implies -7 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-24=-7[x-(-4)]\implies y-24=-7(x+4)

7 0
3 years ago
There are x sparrows in a tree. There are 50 sparrows on the ground beneath the tree. Let y represent the total number of sparro
Ganezh [65]
X+50=y I think that's how you do it.

7 0
4 years ago
Read 2 more answers
How to answer the paper.
Alexandra [31]

we can simply pick any two points off the x,y table, so


\bf \begin{array}{|cc|ll}
\cline{1-2}
x&y\\
\cline{1-2}
0&20\\
3&11\\
6&2\\
9&-7\\
\cline{1-2}
\end{array}
\begin{array}{llll}
\\[1em]
\leftarrow \textit{let's use this point}\\\\
\leftarrow \textit{and this point}
\end{array}~\hspace{5em}
(\stackrel{x_1}{3}~,~\stackrel{y_1}{11})\qquad
(\stackrel{x_2}{9}~,~\stackrel{y_2}{-7})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-7-11}{9-3}\implies \cfrac{-18}{6}\implies -3

8 0
3 years ago
Solve the following expressions using logarithm and Antilogarithm .
katrin [286]

Answer:

  1. 0.01688496
  2. 0.3449537
  3. 0.05002308
  4. 2.0375623
  5. 0.4162862

Step-by-step explanation:

<u>Some formulas to help</u>

  • <em>log ab = log a + log b</em>
  • <em>log a/b = log a - log b</em>
  • <em>log a^b = b log a</em>
  • <em>antilog (log a) = a, antilog is the inverse of log</em>
  • <em>get values of log and antilog by using calculator or online calculator ( I used online calculator for this problem)</em>
  • <em>round numbers as required, I left them as is</em>

1. Let the number be x, solving to show the method

  • √0.0002851 = x
  • log √0.0002851 = log x
  • 1/2 log 0.0002851 = log x
  • 1/2(-3.545) = log x
  • log x = -1.7725
  • antilog (log x) = antilog (-1.7725)
  • x = 0.01688496

2. Short of the above method, will apply to this and following

  • \sqrt[7]{0.0005812} =
  • antilog (1/7 log (0.0005812)) =
  • antilog (1/7(-3.23567439437)) =
  • antilog (-0.46223919919) =
  • 0.3449537

3. .........................................

  • 2.714^3 =
  • antilog (log 2.714^3) =
  • antilog (3 log 2.714) =
  • antilog (3*0.43360984332) =
  • antilog (1.30082952996) =
  • 0.05002308

4..........................................

  • 35.12^(1/5) =
  • antilog (1/5 log (35.12)) =
  • antilog (1/5*1.54555450723)
  • antilog (0.30911090144) =
  • 2.0375623

5. .........................................

  • (0.07214)^(1/3) =
  • antilog ( 1/3 log (0.07214)) =
  • antilog (1/3*(-1.14182386202 )) =
  • antilog ( --0.380607954 )=
  • 0.4162862

Let me know if anything is not clear. Hope it helps.

5 0
3 years ago
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