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umka2103 [35]
3 years ago
8

The function h(t) = -4.9t2 + h0 gives the height (h), in meters, of an object t seconds after it falls from an initial height (h

0). The table shows data for a pebble that fell from a cliff.
TIME HEIGHT
1 55.1
2 40.4
3 15.9

To the nearest tenth of a second, how long after the pebble falls will it hit the ground?
Mathematics
2 answers:
sveticcg [70]3 years ago
7 0
It will hit the ground after 3.499 seconds.

To solve this you first have to find the value of h(0) in this equation. That is the height from which it was dropped.

You can input any of the points into the equation and solve for the missing part. You will get 60 for the height.

The use the quadratic formula to see that it reaches the ground after 3.499 seconds.
vodomira [7]3 years ago
5 0

Answer:

Equation: h(t)=- 4.9(t)^2 + 60

Seconds: 3.5

Step-by-step explanation:

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Answer:

x=4

Step-by-step explanation:

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Multiply each side by RT

RT sin 60 = 2 sqrt(3)

Divide by sin 60

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RT = 4

Then

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Help, i know the answer but i don’t know how to do the work
Diano4ka-milaya [45]

Answer:

C

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying each radical before combining them.

\sqrt{45t}

= \sqrt{9(5t)}

= \sqrt{9} × \sqrt{5t} = 3\sqrt{5t}

-----------------------------------------------------------------------------

\sqrt{125t}

= \sqrt{25(5t)}

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---------------------------------------------------------------------------

Hence

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postnew [5]
Answer:
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