The value of integration of y=16-
from x=-1 to x=1 is 94/3.
Given the equation y=16-
and the limit of the integral be x=-1,x=1.
We are required to find the value of integration of y=16-
from x=-1 to x=1.
Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.
Integration is basically opposite of differentiation.
y=16-
Find the integration of 16-
.
=16x-
Now find the value of integration from x=-1 to x=1.
=16(1)-
-16(-1)-
=16(1)-1/3+16-1/3
=32-2/3
=(96-2)/3
=94/3
Hence the value of integration of y=16-
from x=-1 to x=1 is 94/3.
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Answer:
6
Step-by-step explanation:
root the 216 as it is a cube
:edge *edge *edge =volume
Since all edges are the same, just root it
I hope this helped if it did please mark me Brainliest
Answer:
x = 2
Step-by-step explanation:
5x - 6 = 4
add 6 to each side
5x = 10
divide each side by 5
x = 2
Assuming you meant square root of 90 it would be
90 equals 3 times the square root of 10
√90 = 3√10