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3 years ago

5x (5x3+9^2)+4 I got 28x^2+88 I know i wrong but idont know how to do the problem.

Mathematics

1 answer:

Nataliya [291]3 years ago

6 0

Distribute the 5x to the contents of the inner parentheses to get $5x^4+405x+4$ 5x^4+

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Random list of rational numbers

vagabundo [1.1K]

1/3, 2/4, 1/5, 9/3, etc....

5 0

2 years ago

The two top NBA players played a basketball game against the RSM team. Together the NBA players made 85 baskets, scoring one poi

sergejj [24]

Answer:

54 three- point field goals

Step-by-step explanation:

184 points = <em>x </em>free throws and 3<em>y </em> three-point field goals

x= 22 free throws, each one is 1 point

184 - 22 = 162

162 ÷ 3 = 54

54=y

54 three point field goals

7 0

2 years ago

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Which expression is equivalent to 8g + 2 + 4g − 2 − 2g?

LekaFEV [45]

Answer:

B) 10g

Step-by-step explanation:

Collect like terms

8g + 4g - 2g = 10g

2 - 2 = 0

10g + 0= 0

4 0

2 years ago

What is the x intercept of the line below?

maw [93]

Answer:

No x-intercept

Step-by-step explanation:

When there's an equation that has no x then it will not touch the x axis.

8 0

2 years ago

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A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$