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3 years ago

5x (5x3+9^2)+4 I got 28x^2+88 I know i wrong but idont know how to do the problem.

Mathematics

1 answer:

Nataliya [291]3 years ago

6 0

Distribute the 5x to the contents of the inner parentheses to get $5x^4+405x+4$ 5x^4+

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The diameter of a sphere with a volume of 121.5 cubic mm is ___ mm.

Scorpion4ik [409]

Answer:

Diameter= 6.15

Step-by-step explanation:

Like the radius explanation but multiply the answer by 2.

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2 years ago

Soo I need help... can u help?

Luda [366]

Answer:

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3 years ago

Read 2 more answers

A pile of sand in the shape of a cone has a diameter of 8 in. and a height of 5 in.

max2010maxim [7]

if it has a diameter of 8, that means its radius is half that, or 4.

$\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}~~
\begin{cases}
r=radius\\
h=height\\[-0.5em]
\hrulefill\\
r=4\\
h=5
\end{cases}\implies V=\cfrac{\pi (4)^2(5)}{3}\implies V=\cfrac{80\pi }{3}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill \stackrel{using~\pi =3.14}{V= 83.7\overline{3}}~\hfill$

8 0

2 years ago

Please help! Thanks in advance.

alukav5142 [94]

In this problem, we need to plug in the given x values for $f(x)=0$ and find a and b.

When we plug in 1, we get: $2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0$

Simplify:
$2 - 5 - 14 + a + b = 0$
$- 17 + a + b = 0$
$a + b = 17$

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
$2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0$
$512 - 320 - 224 + 4a + b = 0$
$- 32 + 4a + b = 0$
$4a + b = 32$

Now we have our second one. We can combine them:
$a + b = 17 \\ 4a + b = 32$

I use elimination method which is easier here.

Multiply the top equation by -1: $- a - b = - 17 \\ 4a + b = 32$

Add them up:
$3a = 15$

Simplify:
$a = 5$

Now we have a, we can plug in one of those equations to find b:
$5 + b = 17$
$b = 17 - 5$
$b = 12$

So, the answers are $a=5$ and $b=12$ .

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3 years ago

The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp

Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .