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dybincka [34]
2 years ago
5

Helpppp pleaseeee ????

Mathematics
1 answer:
Agata [3.3K]2 years ago
3 0

Answer:

LQ = 54

Median = 69

UQ = 94

Step-by-step explanation:

This list is already sorted for you, so you don't need to worry about that, otherwise you would need to sort the numbers in ascending order. To find the median, we do \frac{n+1}{2}, where n is the amount of numbers. This gives us 4, so the median is at position 4, so the median is 69. The lower quartile is simply \frac{n+1}{4}, so 2, so the lower quartile is 54. The upper quartile is \frac{n+1}{2} X 3, so 6, so the upper quartile is 94.

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PLSS HELP ME I AM GOING TO CRY IF I DONT GET THIS ANSWER PLSS HELP ME What is the slope-intercept equation of the line below?
mr Goodwill [35]

Answer:

y = -3x + 4

Step-by-step explanation:

Hey!

==================================================================

Slope-Intercept Form: y - mx + b, where m is the slope and b is the y-intercept (point where x =0).

Since we know that the slope is -3, we substitute that in for m.

⇒y = -3x + b

Now, we know the y-intercept is 4, so we substitute that in for b:

⇒y = -3x + 4

==================================================================

<em>Hope I Helped, Feel free to ask any questions to clarify :) </em>

<em> Have a great day! </em>

<em> More Love, More Peace, Less Hate. </em>

<em>        -Aadi x </em>

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Step-by-step explanation:


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If Kevin wants a 90 average in math after 5 tests and his first 4 tests are 76, 92, 89 and 97 what does he need on the fifth tes
Keith_Richards [23]
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
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4 years ago
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