Answer:
Null hypothesis: u = 8.8 liters
Alternative hypothesis: u < 8.8 liters
Step-by-step explanation:
The null hypothesis is always opposite to Tue alternative hypothesis and is the default hypothesis.
In this case study, the null hypothesis is that the average American consumes 8.8 liters of alcohol per year: u = 8.8
The alternative hypothesis is that does the average American consumes less than 8.8 liters of alcohol per year: u < 8.8 liters
Answer:
Step-by-step explanation:
If a point (x, y) is translated by 4 units horizontally right and 1 unit upwards, coordinates of the image point will be,
(x, y) → (x + 4. y + 1)
Therefore, vertices of the image triangle ABC will be,
A(2, 2) → A'(2+4, 2+1)
→ A'(6, 3)
B(5, -1) → B'(5+4, -1+1)
→ B'(9, 0)
C(1, -2) → C'(1+4, -2+1)
→ C'(5, -1)
Then reflected across y-axis.
Rule for the reflection across y-axis will be,
(x, y) → (-x, y)
A'(6, 3) → A"(-6, 3)
B'(9, 0) → B"(-9, 0)
C'(5, -1) → C"(-5, -1)
Answer:
No
Step-by-step explanation:
Because 10 - 6.79 = 3.21
Answer:
- C.) obtuse triangle
- 39°
- 167°
- D.) 111°
Step-by-step explanation:
1. The sum of angles in a triangle is 180°. The sum of the given angles is less than 90°, so the remaining angle must be more than 90°. When the largest angle is more than 90°, it is an obtuse angle. A triangle with an obtuse angle is classified as obtuse.
__
2. The sum of the interior angles is 180°, so we have ...
x° +39° +102° = 180°
x° = 39° . . . . . . . . . . . subtract 141°
__
3. The third interior angle is the supplement to the sum of the given interior angles. Likewise, x° is the supplement to the third interior angle, so its value is the same as the sum of the two given interior angles. (The rule is often stated as "an exterior angle is equal to the sum of the remote interior angles.")
x° = 130° +37°
x° = 167°
__
4. Same deal as problem 3:
x° = 75° +36°
x° = 111°
Answer:
The endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).
Step-by-step explanation:
If a line connecting the midpoint of two sides and parallel to the third side of the triangle, then it is called a midsegment.
From the given figure it is noticed that the vertices of the triangle are D(1,4), E(1,1) and F(-3,3).
If the midsegment is parallel to DE, then the end points of the midsegment are mid point of DF and EF.
Midpoint formula.
Midpoint of DF,
Midpoint of EF,
Therefore the endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).
