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Zarrin [17]
3 years ago
12

Divide. Write your answer in simplest form. 4 ÷ 5/6

Mathematics
1 answer:
iren [92.7K]3 years ago
6 0
4 / (5/6)

4 x (6/5)                    - flip the fraction and flip the second number

4 x (6/5) =  4.8

4.8 is your answer

hope this helps
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Quadrilateral JKLM is graphed with vertices at J(-2,2), K(-1,-5), L(4,0), and M(3,7).
AveGali [126]

Answer:

<u>Question (a)</u>

Midpoint of a line segment:

M=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{midpoint of }JL=\left(\dfrac{-2+4}{2},\dfrac{2+0}{2}\right)=(1,1)

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{midpoint of }MK=\left(\dfrac{3-1}{2},\dfrac{7-5}{2}\right)=(1, 1)

<u>Question (b)</u>

Find slopes (gradients) of JL and MK then compare.  If the product of the slopes of JL and MK equal -1, then JL and MK are perpendicular.

\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{slope of }JL=\dfrac{0-2}{4+2}=-\dfrac13

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{slope of }MK=\dfrac{-5-7}{-1-3}=3

\textsf{slope of }JL \times \textsf{slope of }MK=-\dfrac13 \times3=-1

Hence segments JL and MK are perpendicular

4 0
1 year ago
PLEASE HEEEELP MEEE ;(
klio [65]

Answer:

Hey there!

a. 2x+5=30

b. 1/3x-8=x+1

c. 3=21/(x+5)

d. 3x-5=46

For the picture

a. y=7x+60

b. y=5x+120

c. 7x+60=5x+120

Let me know if this helps :)

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The least is 0.015 because it is less than the others due to the fact that it is far away from the decimal point on the right side
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iVinArrow [24]

Answer:

all work is shown and pictured

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irinina [24]
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