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Maslowich
3 years ago
7

Find the x-intercept:

Mathematics
2 answers:
egoroff_w [7]3 years ago
3 0

Answer:

64

Step-by-step explanation:

WITCHER [35]3 years ago
3 0
64 is the answer ......
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A store sells a package of comic books with a poster. A poster and three comic books cost $10.50. A poster and 12 comics cost $1
NikAS [45]

answer:

there you goooo

Explanation

4 0
3 years ago
Kenneth signed up to receive Internet service for $13 per month plus a $30 start-up fee. Which equation could be used to find th
zimovet [89]

The equation 13x+30=134 can be used to find the number of months Kenneth can receive internet service.

Step-by-step explanation:

Given,

Start up fee to receive internet = $30

Per month charges = $13

Total amount = $134

Let,

x be the number of months.

y be the total cost.

y = 13x+30

Putting y=134

134=13x+30\\13x+30=134

The equation 13x+30=134 can be used to find the number of months Kenneth can receive internet service.

Keywords: equation, addition

Learn more about addition at:

  • brainly.com/question/1836777
  • brainly.com/question/1993757

#LearnwithBrainly

7 0
3 years ago
Math<br> My fatal weakness<br> Especially on Fridays
swat32

Answer:

1 is 28 as it is just asking the area (At least I think)

2 is 22 as it is perimeter

Step-by-step explanation:

4x7 is 28 (For one)

8 (4+4) + 14 (7+7) = 22

Have a great day!

4 0
3 years ago
Determine whether each of the binary relation R defined on the given sets A is reflexive, symmetric, antisymmetric, or transitiv
ki77a [65]

Answer:

In explanation

Please let me know if something doesn't make sense.

Step-by-step explanation:

a)

*This relation is not reflexive.

0 is an integer and (0,0) is not in the relation because 0(0)>0 is not true.

*This relation is symmetric because if a(b)>0 then b(a)>0 since multiplication is commutative.

*This relation is transitive.

Assume a(b)>0 and b(c)>0.

Note: This means not a,b, or c can be zero.

Therefore we have abbc>0.

Since b^2 is positive then ac is positive.

Since a(c)>0, then (a,c) is in R provided (a,b) and (b,c) is in R.

*The relation is not antisymmretric.

(3,2) and (2,3) are in R but 3 doesn't equal 2.

b)

*This relation is reflective.

Since a^2=a^2 for any a, then (a,a) is in R.

*The relation is symmetric.

If a^2=b^2, then b^2=a^2.

*The relation is transitive.

If a^2=b^2 and b^2=c^2, then a^2=c^2.

*The relation is not antisymmretric.

(1,-1) and (-1,1) is in the relation but-1 doesn't equal 1.

c)

*The relation is reflexive.

a/a=1 for any a in the naturals.

*The relation is not symmetric.

Wile 4/2 is an integer, 2/4 is not.

*The relation is transitive.

If a/b=z and b/c=y where z and y are integers, then a=bz and b=cy.

This means a=cyz. This implies a/c=yz.

Since the product of integers is an integer, then (a,c) is in the relation provided (a,b) and (b,c) are in the relation.

*The relation is antisymmretric.

Assume (a,b) is an R. (Note: a,b are natural numbers.) This means a/b is an integer. This also means a is either greater than or equal to b. If b is less than a, then (b,a) is not in R. If a=b, then (b,a) is in R. (Note: b/a=1 since b=a)

6 0
3 years ago
Evaluate the function.<br> Find f(O) when f(x) = x2 + 5x - 6.
brilliants [131]

Answer:

The answer is -6.

Step-by-step explanation:

0^2 = 0

5(0) = 0

0+0-6=-6

3 0
3 years ago
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