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mars1129 [50]
3 years ago
13

Solving systems by elimination.

Mathematics
1 answer:
Anna71 [15]3 years ago
5 0

Answer:

These are the answers :) If you have any questions feel free to ask!

1. (1,3)

2. (6,6)

3. (-1,-2)

4. (6,3)

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I NEED MAJOR HELP ON THESE QUESTIONS!!!
Oliga [24]
On the bottom left, the answer is subtraction property of equality because you need to subtract 4x to the 7x to simplify the equation.
4 0
3 years ago
Multiply y^2-16/2y . 5y/y-4
alisha [4.7K]
So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
=y^2-4^2=(y+4)(y-4)
=5(y+4)(y-4)
=5(y+4)(y-4)/2(y-4)
Cancel the common factor y-4
=5(y+4)/2
Answer: 5(y+4)/2



5 0
3 years ago
If ∠C and ∠D are complementary angles, m∠C = (4x + 3)°, find m∠D = (15x - 8)°, find m∠D.
kykrilka [37]

Answer:

67

Step-by-step explanation:

4x+3+15x-8=90(complementary angle)

x=5

now D = 15*5-8

d=67

8 0
3 years ago
What is the answer to the question
Minchanka [31]
D'
you can't use the same single letter to mark a new point.
3 0
3 years ago
Simplify <br><img src="https://tex.z-dn.net/?f=%20%20%5Csqrt%7B%20-%20180%7D%20" id="TexFormula1" title=" \sqrt{ - 180} " alt="
QveST [7]

Answer: (6\sqrt{5})i

This is the same as saying 6i\sqrt{5}

====================================================

Work Shown:

\sqrt{-180} = \sqrt{-1*36*5}\\\\\sqrt{-180} = \sqrt{-1}*\sqrt{36}*\sqrt{5}\\\\\sqrt{-180} = i*6*\sqrt{5}\\\\\sqrt{-180} = 6i\sqrt{5}\\\\\sqrt{-180} = (6\sqrt{5})i\\\\

where i = \sqrt{-1}

As the steps show above, the idea is to factor the radicand into smaller pieces where one of those pieces is the largest perfect square possible. In this case, 36 is the largest factor of 180 that's a perfect square. Then I used the rule \sqrt{A*B} = \sqrt{A}*\sqrt{B} to break up the root.

The parenthesis used at the very end is to help separate the 6\sqrt{5} from the i term. The "i" is not under the square root.

4 0
3 years ago
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