Answer:
x=5±√−103/8
Step-by-step explanation:
There's no real solutions
4x2−3x+9−(2x+1)=2x+1−(2x+1)
4x2−5x+8=0
x=−b±√b2−4ac/2a
x=−(−5)±√(−5)2−4(4)(8)/2(4)
x=5±√−103/8
Answer : (12,4)
that is the max point
Answer:
596.34m approx
Step-by-step explanation:
Given data
Let the Starting point be x
A helicopter flew north 325 meters from x
Then flew east 500 meters
Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position
x^2= 325^2+500^2
x^2=105625+250000
x^2= 355625
x= √355625
x=596.34m
Hence the distance from the starting point is 596.34m approx