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2 years ago

An 8-kN force is applied over an area of 2 cm^2. What is the stress?

Engineering

2 answers:

adell [148]2 years ago

8 0

Answer:

40MPA

Explanation:

Diano4ka-milaya [45]2 years ago

5 0

Answer:

I wrote 40 MPa for this question.

Explanation:

I know that 1 MPa = 1 N / mm^2 so I converted kN to N and mm^2 to cm^2. This helped me use the equation to solve.

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3. A power cycle operates between hot and cold reservoirs at 500 K and 310 K respectively. At steady state the power output deve

grin007 [14]

Answer:

0.163 MW

Explanation:

To get the minimum rate of energy rehection by heat transfer to cold reservoir, it implies that the power cycle operates in reversible cycle. The efficiency of reversible cycle whose value will be same as efficiency of power cycle will be given by

Efficiency of reversible cycle

n= (Th-Tc)/Th where T represent temperature, n efficiency, subscripts h and c hot and cold respectively

Substituting 500 and 310 for hot and cold temperatures respectively then efficiency

n=(500-310)/500=0.38

Efficiency of power cycle, n= Power output/Qh

Qh= 0.1/0.38= 0.263

Net power output, W= Qh- Qc

Qc=Qh-W= 0.263-0.1=0.163 MW

4 0

3 years ago

1. (15) A truck scale is made of a platform and four compression force sensors, one at each corner of the platform. The sensor i

Elanso [62]

Answer:

a). 139498.24 kg

b). 281.85 ohm

c). 10.2 ohm

Explanation:

Given :

Diameter, d = 22 m

Linear strain, $\epsilon$ = 3%

= 0.03

Young's modulus, E = 30 GPa

Gauge factor, k = 6.9

Gauge resistance, R = 340 Ω

a). Maximum truck weight

σ = Eε

σ = $0.03 \times 30 \times 10^9$

$\frac{P}{A} =0.03 \times 30 \times 10^9$

$P = 0.03 \times 30 \times 10^9\times \frac{\pi}{4}\times (0.022)^2$

= 342119.44 N

For the four sensors,

Maximum weight = 4 x P

= 4 x 342119.44

= 1368477.76 N

Therefore, weight in kg is $m=\frac{W}{g}=\frac{1368477.76}{9.81}$

m = 139498.24 kg

b). Change in resistance

$k=\frac{\Delta R/R}{\Delta L/L}$

$\Delta R = k. \epsilon R$ , since $\epsilon= \Delta L/ L$

$\Delta R = 6.9 \times 0.03 \times 340$

$\Delta R = 70.38$ Ω

For 4 resistance of the sensors,

$\Delta R = 70.38 \times 4 = 281.52$ Ω

c). $k=\frac{\Delta R/R}{\epsilon}$

If linear strain,

$\frac{\Delta R}{R} \approx \frac{\Delta L}{L}$ , where k = 1

$\Delta R = \frac{\Delta L}{L} \times R$

$\Delta R = 0.03 \times 340$

$\Delta R = 10.2$ Ω

4 0

2 years ago

A small object A is held against the vertical side of the rotating cylindrical container of radius r by centrifugal action. If t

xxMikexx [17]

Answer:

el radius es coeficiente por que determina la expresión

8 0

2 years ago

4. What are these parts commonly called?

patriot [66]

These parts are commonly called carburetor emulsion tubes. These tubes maintain the air-fuel ratio at different speeds.

The carburetor is a device of the combustion engine power supply system that mixes fuel and air in order to facilitate internal combustion.

The carburetor emulsion tubes are tubes that maintain the air-fuel ratio at different velocities.

These tubes (carburetor emulsion tubes) are small brass cylinders where the metering needle slides into them.

Learn more about carburetors here:

brainly.com/question/4237015

7 0

2 years ago

Determine the magnitude and direction angles of F2, so that the resultant of the two forces acts upward along the z-axis of the

sergejj [24]

Answer:Check the attached

Explanation:

4 0

2 years ago