Anyone really , but you must be enrolled in an agriculture course at your school.
Answer: efficient communication between engineers and teams
Explanation: Concurrent engineering concept or design is a strategy where all the tasks involved in product development are done in parallel. It is an approach used in product development in which all functions are integrated to reduce the time required to bring a new product to market.
One of the major challenges engineering managers face here is effective and efficient communication. To start with, every member of the team must know the design goals/objectives and must be aware of the interrelationships between all aspects of the design process, therefore there is need for superior communication between all sections of the company.
There are now service providers who not only train people on how to perform concurrent design effectively, but also provide the necessary tools to enhance communication between the team members.
Answer:
y = 56
Explanation:
We label each of the given equations as follows;
4·x + 2·y = 20...(1)
-8·x - 3·y = 16...(2)
Therefore, we are given a simultaneous equation, question
We make 'x' the subject of both equations and equate the result to find the value of 'y' as follows;
For equation (1)
4·x + 2·y = 20
∴ x = (20 - 2·y)/4 = 5 - y/2
x = 5 - y/2
For equation (2), we have;
-8·x - 3·y = 16
∴ x = (16 + 3·y)/(-8) = -2 - 3·y/8
x = -2 - 3·y/8
Equating the two equations of 'x', gives;
5 - y/2 = -2 - 3·y/8
7 = y/2 - 3·y/8 = (4·y - 3·y)/8 = y/8
∴ 7 = y/8
y = 7 × 8 = 56
y = 56
Answer:
(a) 6.5774 minutes
(b) 4.3879 minutes
(c) 2.459 minutes
(d) 245.902 minutes
Explanation:
The learning curve model follows the following equation:
where Y are the units time to produce X units, and a is the time for assembly the first unit. Additionally, b is calculated as:
Where r is the learning rate for mechanical assembly. So, b is equal to:
Then, the equation is:
Finally, the unit times to produce the second unit are:
The 10th unit:
The 100th unit:
Then, the total cumulative time T to produce 100 units in the Crawford model is calculated as:
Answer:
The minimum diameter to withstand such tensile strength is 22.568 mm.
Explanation:
The allow is experimenting an axial load, so that stress formula for cylidrical sample is:
Where:
- Normal stress, measured in kilopascals.
- Axial load, measured in kilonewtons.
- Cross section area, measured in square meters.
- Diameter, measured in meters.
Given that and , diameter is now cleared and computed at last:
The minimum diameter to withstand such tensile strength is 22.568 mm.