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Monica [59]
2 years ago
10

There were 100 pizzas sold at Romeo's Pizzeria on Tuesday. A large pizza costs $16 and a small pizza costs $11. If $1,550 worth

of pizzas were sold in all, how many small pizzas were sold?​
Mathematics
1 answer:
Blizzard [7]2 years ago
7 0

Answer:

  • 10 small pizzas sold

Step-by-step explanation:

Let number of large pizzas be l and number of small be s.

<u>Then we have equations:</u>

  • l + s = 100
  • 16l + 11s = 1550

<u>From the first equation, we get l = 100 - s and substitute in the second equation:</u>

  • 16(100 - s) + 11s = 1550
  • 1600 - 16s + 11s = 1550
  • 5s = 1600 - 1550
  • 5s = 50
  • s = 10

Number of small pizzas is 10

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Suppose the discrete random variable X has the probability distribution below:
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3 years ago
The cheerleading team lines up down the football field to rally the spectators. If there are 12 cheerleaders, which
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8 0
3 years ago
A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a
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Answer:

y=-\dfrac{13}{49}x^2

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

y=ax^2+bx+c

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

-13=a(-7)^2+b(-7)+c

49a-7b+c=-13

(x,y) = (7,-13)

-13=a(7)^2+b(7)+c

49a+7b+c=-13

(x,y) = (0,0)

0=a(0)^2+b(7)+c

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so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13

49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13

we can solve these two equation using the elimination method, by simply adding the two equations

\quad\quad49a-7b=-13\\+\quad49a+7b=-13

------------------------------

\quad\quad 98a=-26

\quad\quad a=-\dfrac{13}{49}

Now we can plug this value of a in any of the two equations.

49a-7b=-13

49\left(-\dfrac{13}{49}\right)-7b=-13

-13-7b=-13

-7b=0

b=0

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

y=\left(-\dfrac{13}{49}\right)x^2+0x+0

y=-\dfrac{13}{49}x^2

49y=-13x^2

This our equation of the arch!

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