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kozerog [31]
2 years ago
10

Samir bought 3 pounds of cement to repair the crack in his sidewalk each crack needs to be filled with 2 oz of cement part a how

can he convert 3 pounds to ounces use the drop-down menus to explain "blank" three by "blank" part b how many cracks can he repair? Enter your Answer in the box " blank" cracks
Mathematics
1 answer:
krek1111 [17]2 years ago
7 0
Uhm let’s see how about part b
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3 years ago
“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor
Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

C=2\pi r

<u><em>Find the radius of the sphere with a 5.50-meter circumference</em></u>

For C=5.50\ m

assume

\pi =3.14

substitute and solve for r

5.50=2(3.14)r

r=5.50/[2(3.14)]=0.88\ m

<u><em>Find the radius of the sphere with a 7.85-meter circumference</em></u>

For C=7.85\ m

assume

\pi =3.14

substitute and solve for r

7.85=2(3.14)r

r=7.85/[2(3.14)]=1.25\ m

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

SA=4\pi r^{2}

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For r=0.88\ m

assume

\pi =3.14

substitute

SA=4(3.14)(0.88)^{2}

SA=9.73\ m^{2}

<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For r=1.25\ m

assume

\pi =3.14

substitute

SA=4(3.14)(1.25)^{2}

SA=19.63\ m^{2}

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

9.73*(92)=\$895.16

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

19.63*(92)=\$1,805.96

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0
3 years ago
Find the value of the variable
marissa [1.9K]

Answer:

x=13

Step-by-step explanation:

because they're alternate adjacent angles:

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8 0
3 years ago
The intersection of the two lines, shown in the image below, creates special angle relationships between angles 1,2,3,
levacccp [35]

Answer:

3 and 4

1 and 3

Step-by-step explanation:

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3 years ago
Is it reasonable if so or if not tell me the equation
lianna [129]
His answer is not reasonable because 5/8>4/3
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2 years ago
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