Label the 3 distinct sides of the box. I arbitrarily chose the letters a, b and c.
Use the info about areas as follows:
ab=54 in^2
ac=90 in^2
bc=60 in^2
Here you have 3 equations in 3 unknowns (a, b and c), which is enough info to use to determine a, b and c. Then the volume of the box is a*b*c.
Example: bc = 90, but c = 60/b. You could subst. 60/b for c in the 2nd and 3rd equation, which will eliminate c completely and leave you with 2 equations in 2 unknowns.
Continuing this procedure, I determined that a=9, b=6 and c=10. Thus, the volume of the box is V = 9*6*10 = 540 cubic inches (answer)
By conservation of linear amount of movement we have:
m1v1i + m2v2i = m1v1f + m2v2f
Where,
v1i = v2i = 0 (assuming initial rest)
m1v1f + m2v2f = 0
Substituting the values:
m1 (-3) + (1) (150) = 0
Clearing m1:
m1 = (- (1) * (150)) / (- 3)
m1 = 50 Kg
answer:
his mass is 50 Kg
1) acknowledge the rule that anything that’s outside of the bracket applies to EVERYTHING inside of the bracket
2)apply the rule: (A-6)^2
Answer:
x = 2.5 or 7.5
Step-by-step explanation:
Subtract 3/4.
|5 -x| = 10/4 = 2.5
This resolves to two equations:
- 5 -x = 2.5 ⇒ x = 5 -2.5 = 2.5
- 5 -x = -2.5 ⇒ x = 5 +2.5 = 7.5
The solutions are x = 2.5 or 7.5.
The answer your looking for is 7.5ft by 1.5ft hope this helped have a nice day :)
