Answer:
The program in C++ is as follows:
#include <iostream>
#include <vector>
using namespace std;
int main(){
vector<int> nums;
int num;
cin>>num;
while(num != -1){
nums.push_back(num);
cin>>num; }
for (auto i = nums.begin(); i != nums.end(); ++i){
cout << *i <<endl; }
return 0;
}
Explanation:
This declares the vector
vector<int> nums;
This declares an integer variable for each input
int num;
This gets the first input
cin>>num;
This loop is repeated until user enters -1
while(num != -1){
Saves user input into the vector
nums.push_back(num);
Get another input from the user
cin>>num; }
The following iteration print the vector elements
<em> for (auto i = nums.begin(); i != nums.end(); ++i){
</em>
<em> cout << *i <<endl; }
</em>
Well, it is safe to turn a computer on without a RAM, but you can't really do it. RAM is one of the essential components in computers without which you can't really use a computer. You can turn it on, however, nothing will appear on your screen and the system won't boot. So, technically, it is safe, but it won't do anything to your computer as it cannot run without RAM.
Answer:
error: incompatible types
Explanation:
Given
The attached code
Required
The output
Variable "a" is declared as float
While p is declared as a pointer to an integer variable
An error of incompatible types will be returned on line 3, <em>int *p = a;</em>
Because the variables are not the same.
To assign a to p*, we have to use type casting.
Hence, (b) is correct
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In python:
##Specifies the range that the variable 'number' should change within
for number in range(2,10):
##Prints the decimal equivalent of each fraction
print(1 / number)
