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alexandr402 [8]
4 years ago
14

Solve 20x + 5y= for y

Mathematics
2 answers:
mylen [45]4 years ago
4 0
The correct answer is y=-4
Mama L [17]4 years ago
3 0

Answer:

<h2>y = -4x</h2>

Step-by-step explanation:

Solve 20x + 5y =  for y

20x + 5y = 0

subtract 20x both sides

5y = -20x

simplify:

y = <u>-20x</u>

        5

finally

y = -4x

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Simplify -12x^4/x^4+8x^5
alexgriva [62]

Answer:

OPTION A: $ \frac{12}{1 + 8x} $, where $ x \ne - \frac{1}{8} $.

Step-by-step explanation:

Given: $ \frac{- 12x^4}{x^4 + 8x^5} $

Taking $ x^4 $ common outside in the denominator, we get:

$ = \frac{-12x^4}{(x^4)(1 + 8x)} $

$ x^4 $ will get cancelled on the numerator and denominator, we get:

$ = \frac{-12}{1 + 8x} $

we know that the denominator can not be zero.

That means, 1 + 8x $ \ne $ 0.

$ \implies 8x \ne -1 $

$ \implies x \ne \frac{-1}{8} $

So, the answer is: $ \frac{-12}{1 + 8x} $, where $ x \ne \frac{-1}{8} $.

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4 years ago
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