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Sophie [7]
4 years ago
11

determine the sample sieze erequired to estimate teh mean score on a standardizes test within 4 [pints of the trrue mean with 98

% confidence
Mathematics
1 answer:
Andreas93 [3]4 years ago
5 0

Answer: Minimum sample size = 110

Step-by-step explanation:

Formula to find minimum sample size :

n=(\dfrac{z\times s}{E})^2 , where z = critical z-value for confidence level, s= sample standard deviation , E = margin of error

Given: E= 4 , s= 18

Critical z-value for 98% confidence = 2.327

So,  n=(\dfrac{2.327\times18}{4})^2

=(\dfrac{41.886}{4})^2\\\\=(10.4715)^2=109.65231225\approx110

Minimum sample size = 110

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