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3 years ago

Show that (X+1)(x+3)(x+5)=ax3+bx2+cx+d

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

3 0

Answer:

a = 1

b = 9

c = 23

d = 15

Step-by-step explanation:

Expand it out:

(x^2 + 4x + 3)(x+5)

(x^3 +4x^2 +3x + 5x^2 + 20x + 15)

=x^3 + 9x^2 + 23x +15

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PLEASE HELP! I’ll give brainliest (no links please)

Dafna1 [17]

Answer:

g(x)=2x^2

Step-by-step explanation:

Multiplying by a constant will stretch the graph as shown. The graph of g(x) appears to pass through (1,2), so g(x)=2x^2 is a reasonable guess (I can't see the answer choices).

8 0

3 years ago

Select the correct answer.

valentinak56 [21]

see attached for explanation

I hope it helps

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3 years ago

The Price family and the Jenkins family each used their sprinklers last summer. The water output rate for the Price family's spr

PIT_PIT [208]

Set up two equations:

1st: P (for Price family) + J (for Jenkins family) = 45 hours

2nd: 20P + 35J = 1200 liters

Rewrite the first equation as P = 45 – J

Replace P in the second equation:

20(45-J) + 35J = 1200

Simplify:

900 -20J + 35J = 1200

900 +15J = 1200

Subtract 900 from both sides:

15J = 300

Divide both sides by 15:

J = 300/15

J = 20

Jenkins used theirs for 20 hours

Price used theirs for 45-20 = 25 hours.

7 0

3 years ago

PLS ANSWER THE BELOW QUESTION AND I'LL MARK U AS BRAINLIST

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

$a) \dfrac{3x}{2}-5=4$

Add 5 to both sides

$\dfrac{3x}{2}-5 +5 = 4 + 5\\\\\dfrac{3x}{2} = 9 \\\\Now \ multiply \ both \ sides \ by \ 2 \\\\\dfrac{3x}{2}*2 = 9*2\\\\3x = 18\\Now \ divide \ both \ sides \ by \ 3\\\\x =\dfrac{18}{3}\\\\$

x = 6

$b) \dfrac{x-3}{5} + 1 = -2\\\\\\Subtract \ 1 \ from \ both \ sides\\\\\dfrac{x-3}{5} = -2 -1\\\\\dfrac{x-3}{5} = -3\\\\Multiply \ both \ side \ by \ 5\\\\x - 3 = -3*5\\\\x -3 = -15\\\\$

Add 3 to both sides

x = -15 +3

x = -12

7 0

3 years ago

Read 2 more answers

If f(x) = x-6 and g(x)= 1/2x (x+3), find g(x) * f(x)

sertanlavr [38]

Answer:

Final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

Step-by-step explanation:

given functions are $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

Now we need to find about what is the value of $g\left(x\right)*f\left(x\right)$ .

$g\left(x\right)*f\left(x\right)$ simply means we need to multiply the value of $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

$g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)$

$g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$

Hence final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

5 0

3 years ago