Question

This is urgent I really I need the answers Thanks in advance

Answer 1

equation: 2y = 3x + 15

If cross y-axis, the x will be 0

2y = 3(0) + 15

2y = 15

y = 7.5

crosses y-axis at (0, 7.5)

(b)

P(-1,10), Q(3,4)

(i) gradient:

$\sf \dfrac{y_2-y_1}{x_2-x_1}$

$\rightarrow \sf \dfrac{4-10}{3--1}$

$\rightarrow \sf \dfrac{-6}{4}$

$\rightarrow \sf -1.5$

(ii) midpoint:

$\sf (x_m, y_m) = (\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2})$

$\rightarrow \sf (x_m, y_m) = (\dfrac{3-1}{2}, \dfrac{4+10}{2})$

$\rightarrow \sf (x_m, y_m) = (1,7)$