All categories

2 years ago

Help me I am bad with percentages

Mathematics

1 answer:

Xelga [282]2 years ago

4 0

Answer:

16.67% less

she only made 83% of her anticipated $18,000

Step-by-step explanation:

3000/18000 = 0.1666 or 16.67% less

15000/18000 = 0.8333 or 83%

You might be interested in

100 divided by 32 will give brainliest

Paha777 [63]

Answer: 3.125

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Nitrogen and oxygen are the most abundant gases in Earth’s atmosphere. A nitrogen molecule is 0.00000000003 meters larger than a

Verdich [7]

= 3 × 10-11
(scientific notation)

= 3e-11
(scientific e notation)

= 30 × 10-^12
(engineering notation)
(trillionth; prefix pico- (p))

= 0.0000000000
<span>(real number)</span>

4 0

3 years ago

Read 2 more answers

Simplify the trigonometric expression. 1/1+ sin theta + 1/1-sin theta A, 2 cos^2 theta B. 2 sec^2 theta C. 2 csc^2 theta D. 2 co

Ganezh [65]

So the problem ask to simplify the trigonometric function in your problem and base on the expression and using the theory in simplifying trigonometric function, the answer would be letter B. 2 sec^2 theta. I hope you are satisfied with my answer and feel free to ask for more

3 0

2 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

$P(x \ge 60) \approx P(z > 1.34)$