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Bess [88]
2 years ago
14

I just started learning about rate and I am stuck on a question.(A watch keeps perfect time but only has an hour hand. If the ho

ur hand is three fifths of the distance between 1and2, determine the actual time in hours and minutes)
Mathematics
1 answer:
8090 [49]2 years ago
7 0

Answer:

36 minutes past 1, or 1:36

Step-by-step explanation:

A watch normally has an hour hand that does one revolution in 12 hours.

It takes 1 hour to go from the 1 o'clock position to the 2 o'clock position.

Since 1 hour equals 60 minutes, it takes 60 minutes to go from the 1 o'clock position to the 2 o'clock position.

The hour hand is 3/5 of the way from 1 to 2, so the number of minutes past 1 o'clock is 3/5 of 60 minutes.

3/5 of 60 minutes =

= 3/5 * 60 minutes

= 3/5 * 60/1 minutes

= 180/5 minutes

= 36 minutes

The time is 36 minutes past 1, or 1:36

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Overime- 18.75
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4 0
3 years ago
What is 8/15 plus 2/5 equal to
anastassius [24]

We have to add 8/15 to 2/5.

To add two fractions we have to make them have the same denominator, so we have to convert 2/5 to have a denominator of 15. To do this, we have to multiply 2/5 by 3 and then we can add the fractions:

\begin{gathered} \frac{8}{15}+\frac{2}{5} \\ \frac{8}{15}+\frac{2}{5}\cdot\frac{3}{3} \\ \frac{8}{15}+\frac{6}{15} \\ \frac{14}{15} \end{gathered}

Answer: 14/15

5 0
1 year ago
16x² +8-7x-3x2 - 13x
liq [111]

Answer:

13x^{2}-20x+8

Step-by-step explanation:

Step 1: rearrange the equation

16x^2 - 3x^2 - 7x - 13x +8

Step 2: solve the equation

16x^2 - 3x^2 = 13x^2

-7x - 13x = -20x

(the +8 will stay the same)

so when we put it all together it gives us

13x^2 - 20x + 8

5 0
2 years ago
What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?
mars1129 [50]
The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2

the sum of a geometric seequence is
S_{n}=\frac{a_{1}(1-r^{n})}{1-r}
a1=1
r=2
we want to find S_{10} (since we minus 1, the highest exponet is 9 so add 1 to make it correct)

S_{10}=\frac{1(1-2^{10})}{1-2}
S_{10}=\frac{(1-1024}{-1}
S_{10}=\frac{(-1023}{-1}
S_{10}=1023

3 0
2 years ago
Read 2 more answers
Jacques needs to convert the function f(x) = x2 − 6x + 14 to vertex form, f(x) = (x − h)2 + k, in order to find the minimum.
Anarel [89]

k = 5

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

Since the coefficient of the x² term is 1 then

add/ subtract (half the coefficient of the x-term )² to x² - 6x

f(x) = x² + 2(- 3)x + 9 - 9 + 14 = (x - 3)² + 5 → k = 5


   

5 0
3 years ago
Read 2 more answers
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